Devise a mask for the date format you desire and pass this in with the date e.g.
SELECT [dbo].[DateFormattedByMask] (GETDATE(),'DDDD DD MMM YYYY hh:mi')
could produce
Monday 30 Sep 2013 11:05
Limitations include no option for single digit day and month numbers e.g 24 hours after the previous example gives
Tuesday 01 Oct 2013 11:05
which may be desirable in some circumstances but not all.
/*
YYYY - Year, 4 digit
YY - Year, 2 digit
MMMM - Month name
MMM - Month name, first 3 characters
MM - Month, 2 digit
DDDD - Day of week
DDD - Day of week, first 3 characters
DD - Day of month, 2 digit
hh - hour (24 hour clock, 2 digit)
mi - minutes, 2 digit
ss - seconds, 2 digit
*/CREATE FUNCTION [dbo].[DateFormattedByMask]
(
@InputDate DATETIME,
@Mask NVARCHAR(40)
)
RETURNS VARCHAR(40)
AS
BEGIN
SELECT @Mask = REPLACE(@Mask,'YYYY',DATENAME(YEAR,@InputDate))
SELECT @Mask = REPLACE(@Mask,'YY',RIGHT(DATENAME(YEAR,@InputDate),2))
SELECT @Mask = REPLACE(@Mask,'MMMM', DATENAME(MONTH,@InputDate))
SELECT @Mask = REPLACE(@Mask,'MMM', LEFT(DATENAME(MONTH,@InputDate),3))
SELECT @Mask = REPLACE(@Mask,'MM', RIGHT('0'+CAST(MONTH(@InputDate) AS NVARCHAR(2)),2))
SELECT @Mask = REPLACE(@Mask,'DDDD', DATENAME(dw,@InputDate))
SELECT @Mask = REPLACE(@Mask,'DDD', LEFT(DATENAME(dw,@InputDate),3))
SELECT @Mask = REPLACE(@Mask,'DD', RIGHT('0'+DATENAME(DAY,@InputDate),2))
SELECT @Mask = REPLACE(@Mask,'hh', RIGHT('0'+DATENAME(hh,@InputDate),2))
SELECT @Mask = REPLACE(@Mask,'mi', RIGHT('0'+DATENAME(mi,@InputDate),2))
SELECT @Mask = REPLACE(@Mask,'ss', RIGHT('0'+DATENAME(ss,@InputDate),2))
RETURN @Mask
END
GO 
2014-11-25
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Function do return common datatime formats of a date.
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