Viewing 15 posts - 1 through 15 (of 16 total)
Sorry didn't mean to be vague!
Example:
You have a list of data:
a = 1
b = 2
c = 3
d = [1:1:100] (an array of values 1-100 - 1, 2, 3 ... 100)
Since...
May 8, 2009 at 8:40 am
Jeffrey Williams (4/24/2009)
It sounds like you are trying...
April 24, 2009 at 1:18 pm
Jeffrey Williams (4/24/2009)
When inserting into a table, you have to provide values for all columns that...
April 24, 2009 at 1:06 pm
interestingly enough, I tried going from the successful version i have in SQL 2005 and bring it in to 2008 but all my relational data dissapeared :unsure:
March 13, 2009 at 12:28 pm
I used the Access migration assistant to upsize the database from access 2007 to SQL Server 2005. However, it only transferred the tables, data, and relational information. I have to...
March 13, 2009 at 11:01 am
I'm sorry but could you please clarify?
March 13, 2009 at 7:33 am
Sorry if I wasn't clear before, but in my access system a column value is
"70 or 60 or 81"
and when the query is run that specific value in Access is...
March 13, 2009 at 7:15 am
I have to leave my office until Friday, so pardon my lack of response until then!!
😀
March 11, 2009 at 11:08 am
Msg 245, Level 16, State 1, Line 5
Conversion failed when converting the nvarchar value '77 or 70 or 81' to data type int.
March 11, 2009 at 10:32 am
ah, it seems to be working ok, except that I have a value in "mycolumn" = 70 or 60 or 50" which doesn't successfully convert. Is there a way to...
March 11, 2009 at 9:52 am
Thanks for the reply, I'm still a complete SQL Server newbie so it will take me a bit to get this to work, but I'll post success/failure as soon as...
March 11, 2009 at 9:33 am
Here is exactly what I'm trying to do:
I have a column with various values, but for sake of shortness, one of those values is 65484.
In an Access 2007 query,...
March 11, 2009 at 9:15 am
Have yet to find a working solution to this problem, anyone else have any ideas / pointers / vast amount of awesome knowledge on this issue? 😀
March 11, 2009 at 6:30 am
Thanks for your help, I figured it out. Its a lot easier than it appears at first. 🙂
March 11, 2009 at 6:28 am
Viewing 15 posts - 1 through 15 (of 16 total)