Viewing 15 posts - 916 through 930 (of 954 total)
Wow!
Just caught up from when I posted yesterday... That is a lot of posts about books...
Probably missed the boat on most of these but here goes:
Dune, I have to say...
February 24, 2009 at 8:08 am
The Thread is also a little bit Skynet!
Maybe it/ he will transform in to every scifi computer system/ cyborb...
So long as it does kill the rest of the crew, sorry...
February 23, 2009 at 9:29 am
So either Steve with a list of people receiving their refund
Or
Jeff with his role call of pork chop inductees!
Rodders...
January 16, 2009 at 8:37 am
Steve should have the honour of posting the 1,000 post 😛
Rodders...
January 16, 2009 at 6:24 am
Wow three pages of replies since I went home last night - I must be in the wrong time zone...
On a different note -
...
January 15, 2009 at 1:47 am
I liked this from Gail
This is not the first time that you've criticised the free help that you're getting here. If you want a solution to your exact specs, with...
January 14, 2009 at 9:51 am
Sometimes, however, you get stuck and can't see the forest because of the trees. That's when a fresh perspective on the problem really helps.
I agree, I was going back...
January 14, 2009 at 9:31 am
I'd just like to add my thoughts about the Reporting Services question...
Assuming the OP and bsrlong aren't the same person, and it's not some ruse...
If I were the OP I'd...
January 14, 2009 at 8:53 am
Hi Brad,
This should work:
=MID(A1, FIND("-", A1, FIND("-", A1, FIND("-", A1, 1)+1)+1)+1, LEN(A1) - FIND("-", A1, FIND("-", A1, FIND("-", A1, 1)+1)+1))
There may be an easier way to do it
Oddly enough something...
October 10, 2008 at 3:09 am
Actually they are all listed in BOL together as files, so i would agree with the Question. Helps I got it right as well 😉
ms-help://MS.SQLCC.v9/MS.SQLSVR.v9.en/udb9/html/39e00ebe-c9b7-4d53-90bd-15de2015fd34.htm
Not sure if that works for...
August 28, 2008 at 2:43 am
I beleive you can also write the DELETE this way:
DELETE FROM KP
FROM
KP.[ADD] K LEFT JOIN RP.[ADD] R ON
K.ADX_TYPE = R.ADX_TYPE AND
K.ADX_COMPANY = R.ADX_COMPANY AND
K.ADX_CODE = R.ADX_CODE
WHERE (((R.ADX_TYPE)...
June 9, 2008 at 6:54 am
I don't normally criticise the questions as:
a. This site is free
b. You don't win anything
c. You nearly always learn something even when the question is ambiguous!
But this one is really...
June 5, 2008 at 2:49 am
That will teach me for speed reading the answers - missed the (error results) at the end of answer two! So picked answer 3! My bad...
(But at least I knew...
May 6, 2008 at 3:48 am
Hi All,
So the question forgot to mention which version of SQL Server you are running, and which compatibility level. Obviously 2000 is now so out of date only us poor...
March 31, 2008 at 3:25 am
Viewing 15 posts - 916 through 930 (of 954 total)