Viewing 5 posts - 1 through 5 (of 5 total)
Sql injection will not take place with this code.I already tried.
declare @Inserttbl nvarchar(4000)
declare @TableName varchar(50)
declare @PId varchar(5)
declare @Text varchar(50)
declare @status varchar(5)
set @TableName ='sample'
set @Text = 'Helping hand;Delete table...
December 12, 2016 at 9:37 pm
I already done insertion through parameter only...
December 12, 2016 at 5:31 am
Actually I have done like this.Let me still sql injection take place?
declare @Inserttbl nvarchar(4000)
declare @TableName varchar(50)
declare @PId int
declare @Text varchar(50)
declare @count int
declare @status int
set @TableName ='sample'
set @Text =...
December 12, 2016 at 5:12 am
Thanks @joeroshan for ur help.I have done like this.Here I just printed msg but in reality I will do insert.
declare @Inserttbl nvarchar(4000)
declare @TableName varchar(50)
declare @Text varchar(50)=null
declare @count int
set...
December 12, 2016 at 4:10 am
Thanks for reply.U mean to say like this
declare @Inserttbl nvarchar(4000)
declare @TableName varchar(50)
declare @Text varchar(50)=null
declare @count int
set @TableName...
December 12, 2016 at 3:48 am
Viewing 5 posts - 1 through 5 (of 5 total)