Viewing 12 posts - 1 through 12 (of 12 total)
Hey SSC Veteran,
thanks for the inspiration. HTML tags and some SQL like
select left(convert(varchar(max),anweisungen),CHARINDEX(@Schlagwort,Anweisungen)-1) +'<B><U>' +@Schlagwort+ '</B></U>' +substring(anweisungen,CHARINDEX(@Schlagwort,Anweisungen) + LEN(@Schlagwort),9000) as...
and I am happy π
Regards
Olaf
December 7, 2016 at 2:01 am
These Data are embedded in the polygone (shp-file). In the map are the map, the polygone and the Points witch come from a dataset.
July 13, 2016 at 5:07 am
Hey, here the second function.
ItΒ΄s just for reporting, so the performance is not my top point π
Whats better then while?
create FUNCTION isArbeitstag(@cDatum DATETIME, @typus AS INTEGER)
/*
@cdatum= Datum, das kontrolliert...
February 1, 2016 at 7:42 am
Solution:
Add a new function.
create FUNCTION AnzahlArbeitstage(@Start datetime , @End datetime)
RETURNS int
AS BEGIN
declare @diff int, @C int
select @diff = 0,
@C = datediff(dd,@start,@End)
while @C >0
Begin...
February 1, 2016 at 6:17 am
That's stupid...
The root folder have also permissions... :crying:
That's what I say: When you done everything right, things are working....
December 15, 2015 at 3:33 am
I think that this is not a problem of the 2016.
On an other maschine (2008 + SQL2014) I have the same problem.
Seems that I done something basically wrong.
December 15, 2015 at 3:00 am
All done this,
- IE run as Administrator
- UAC is out
- I am locked on as local Admin on the maschine via rdp
- restart the service everytime.
nothing worked π
The system:...
December 15, 2015 at 2:26 am
Thanks for help
That's what know I found...
select y.Anzahl,x.Jahr
from
(select count(*) as Anzahl,
year(Datum) as Jahr
from KdTickets
where Typ = 1
and infonr = 8233
group by year(Datum)
)y
full join
(select year(getdate())-3 as Jahr
union
select year(getdate())-2 as...
December 14, 2015 at 2:01 am
Hello,
I have in my select a column called "Mitarbeiter". I like to search for Mitarbeiter in ('SB','MS','BE') or Mitarbeiter not in ('SB','MS','BE')
The 'IN' or 'NOT IN' I want to...
October 7, 2015 at 6:29 am
Hey Pieter,
thanks for help. I tryed, but it would not be working.
See what I have done in Screenshot. Maybe it is the wrong point to do that.
Thanks a...
August 31, 2015 at 2:10 am
Viewing 12 posts - 1 through 12 (of 12 total)