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Viewing post 16 (of 16 total)

  • RE: POWER function in SQL server 2005

    Hi

    I am new at SQL, so pls bear with me. How do I use the correction made earlier to correct my code below

    select '1' [union] ,type,SHORTHAND,num,denom,[current],past,round([current]-past,1) current_past,

    round((2.0*num+power(3.0902,2)-3.0902*SQRT(power(3.0902,2)+4.0*num*(1-[current])))/(2.0*(denom+power(3.0902,2))),6) lower_l2,

    round((2.0*num+power(3.0902,2)+3.0902*SQRT(power(3.0902,2)+4.0*num*(1-[current])))/(2.0*(denom+power(3.0902,2))),6)...

Viewing post 16 (of 16 total)