Viewing 15 posts - 31 through 45 (of 59 total)
Thanks for your help guys !
Matt
March 17, 2010 at 4:48 pm
Ron,
I have put your advice to good use and solved the problem.
Thanks very much
Matt
February 28, 2010 at 2:34 pm
Thanks Lutz, this is exactly what I needed. The application uses the 0 date as Jan 1st 1801 so I have to do some conversion work anyway !
Matt
September 6, 2009 at 3:43 pm
Hi,
Thanks for the reply. I've had a look at the thread. I'm not sure it answers my question. I'm looking for the serial date like Excel produces, ie an integer...
September 6, 2009 at 2:44 pm
Hi, that's great I'll give it a go. Thank you
September 2, 2009 at 5:23 pm
Yes, just realised this by playing with it. I thought it would try and group by every variable, I didn't realise it would work out the group by primary key...
August 26, 2009 at 2:57 pm
Once again, thank you for your time.
The cnumber would be something different to the CID. The actual application is that we have a customer table with unique a unique CID...
August 26, 2009 at 2:38 pm
Thanks for your help Matt
I am very grateful. An added complication, what if there is another table called CUSTOMER, and there are is the same CID column. What is I...
August 26, 2009 at 2:09 pm
Thanks Ken,
Looked like I was over complicating it !
Matt
July 10, 2009 at 12:55 pm
Hi Guys,
Thanks all for your help.
I came up with a solution, substitute customers for nurses, orders for jobs and date for weekno
select count(distinct nurses.nurs_id) from nurses join jobs on jobs.nurs_id=nurses.nurs_id
where...
July 8, 2009 at 3:56 pm
Thanks alot, worked fine and I learned something new !
May 15, 2009 at 6:48 am
Thanks for all your help, I shall be reading up in this then.
May 15, 2009 at 4:42 am
Do you get an SSPI error ?
If so read everything you can about SSPI, then give up and use basic SQL authentication.
May 13, 2009 at 4:16 pm
Vijaya Kadiyala (4/14/2009)
Do you want to store "width * height" in WEIGHT column??
Yes, basically. I want actually to do something a bit more exciting, but I just like to understand...
April 14, 2009 at 5:10 pm
davidandrews13 (4/14/2009)
select
x.col1,
x.col2,
'col3' = col1 + col2
from
(select
'col1' = 1 ,
'col2' = 4 ) x
Hi,
Thanks for the info. Unfortunately I cannot quite understand how this fits together. Let's call the...
April 14, 2009 at 11:01 am
Viewing 15 posts - 31 through 45 (of 59 total)