Viewing 3 posts - 1 through 3 (of 3 total)
What I understand if there is value in each column then return true if not then return false.
select Col1, case when coalesce(COl1,'')='' then false else true as Status from...
August 16, 2010 at 10:53 pm
This is complex case:
To resolve this issue you can try the following way--
1. First identify the duplicate based on your requirement (may not duplicate)
2. Find the number of records associated...
May 5, 2009 at 5:13 am
You can use the PIVOT operator to produce this output. To use the PIVOT operator, perform the following steps:
1. Select the data you need by using a special type of...
May 5, 2009 at 12:48 am
Viewing 3 posts - 1 through 3 (of 3 total)
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