Viewing 15 posts - 16 through 30 (of 33 total)
hi,
How do you know that "6U7000000 443 IRA FBO Loelei C Dehart DecD W00001" is 1 row and not any other combination?
Try to add row_number to the query, the row...
January 18, 2011 at 3:45 am
Hi,
I don't sure that this will be faster but try this:
with RecursionCTE (item,Pre,parents)
as
(
select item,
...
October 19, 2010 at 8:46 am
I don't know the question, but 42 is the ultimate answer 🙂
October 4, 2010 at 8:25 am
Hi,
What PP-564103 meant when he said "those two columns should be in select clause!" is that the NEW columns should be in the select like this:
select ee_occup_levels, m, f
from (select...
October 13, 2009 at 3:55 am
Hi,
You can also use the cross tabs as in jefff grate articlae
http://www.sqlservercentral.com/articles/T-SQL/63681/
see also part 2
September 1, 2009 at 9:38 am
Hi,
Did you try useing union?
SELECT '[option value="' + CONVERT(varchar(10),EVENT_TYPE_ID) + '"]' + TYPE_NAME + '[/option]' AS [CURRENT_SELECT]
FROM REF_EVENT_TYPE
WHERE EVENT_TYPE_ID = 1
union all
SELECT '[option value="' + CONVERT(varchar(10),EVENT_TYPE_ID) + '"]' + TYPE_NAME...
August 10, 2009 at 5:28 am
Hi,
Sorry for the late response, at my case the Allow InProcess was enabled on creation.
July 28, 2009 at 12:30 am
Hi,
Just cast\convert all the cols to same data type
DECLARE @t TABLE (col1 VARCHAR (10), col2 int, col3 CHAR (10))
INSERT INTO @t VALUES ('Value 1', 2, 'Value 3')
SELECT...
July 14, 2009 at 1:22 am
Looks like jedi is draw faster then cowboy 😉
July 13, 2009 at 1:47 am
oops, of course, my fault, just made the split my self and was confused :blush:
July 5, 2009 at 2:15 am
July 5, 2009 at 1:09 am
Hi Martin,
As i posted here Problem with linked server,
I have problem with the linked server, it work fine but from time to time I get this error
"Cannot create an instance...
June 11, 2009 at 5:07 am
Jeffrey Williams (5/24/2009)
SELECT Customer.Name AS SortName,
vcltAttrib4_364.ainTVal AS Client_Relationship_Partner,
vFEAttrib4.attInstName AS Partner,
...
May 27, 2009 at 2:54 am
select a.*
from a left outer join on A.ref_no= b.ref_no
where b.ref_no is null
May 19, 2009 at 8:24 am
Viewing 15 posts - 16 through 30 (of 33 total)