Viewing 15 posts - 16 through 30 (of 86 total)
Year would be another column and the query is looking for 2008.
Greg
February 27, 2009 at 11:41 am
It looks like DTYPE is the column name. IN refers to the values inside the parenthesis. Basically it could be rewritten as DTYPE = 'DEPR' OR DTYPE =...
February 27, 2009 at 11:25 am
Although I never figured out why the same stored procedure was behaving differently in the two different environments, I did resolve this issue. I decided to take a completely...
February 27, 2009 at 11:21 am
You can attach the .mdf file without the .ldf file. When you go to attach it, the interface may say log file not found in the lower pane. ...
February 26, 2009 at 6:16 am
GSquared (2/25/2009)
matt stockham (2/25/2009)
Steve Jones - Editor (2/23/2009)
Produce new SKUs? Why not "unlock" features? You have the technology in the XBOX group to unlock things according to some event.
You mean...
February 25, 2009 at 11:29 am
If I understand correctly, you want one total result set instead all of the individual ones. If your iteration is happening in the stored procedure, you can insert them...
February 25, 2009 at 8:16 am
One of the main reasons to use a join is to get data from more than one table. The above query should work assuming that the columns specified are...
February 25, 2009 at 7:56 am
Your open parenthesis is in the wrong place. (exec @sql) should be exec (@sql).
Greg
February 24, 2009 at 1:24 pm
You can query across database using three part naming. For example:
SELECT * FROM Database.Schema.Table
Greg
February 24, 2009 at 11:57 am
Max and min server memory is in MB, so your setting is way too high.
Greg
February 24, 2009 at 10:02 am
Because it's not the only correct answer. Without giving away the answer, the answers were check boxes. You needed to select more than one.
Greg
February 24, 2009 at 9:34 am
I agree with Matt. The pseudo code that you posted doesn't tell us what tables the three columns are from or what the relationships between the tables are, etc....
February 23, 2009 at 9:55 am
Try using ISNULL(COUNT(col2), 0). That should replace the NULL values with a zero.
Greg
February 23, 2009 at 8:42 am
Viewing 15 posts - 16 through 30 (of 86 total)