Viewing 5 posts - 1 through 5 (of 5 total)
So there's always exactly 1S and 1E record? And potentially many As?
If so, join table to itself with 1 side being S and another being E. Create a...
May 8, 2014 at 9:30 am
Sounds good. I don't know why I didn't think of that.
Thanks!
May 8, 2014 at 9:08 am
I have figured something out.
If I create the linked server manually and then run the procedure I get an explicitly raised error that I wrote in to tell me that...
May 8, 2014 at 8:41 am
The creation of the linked server does not fail. I copied the exact line of code and ran it separately on a SQL 2012 machine to create the linked...
May 8, 2014 at 8:19 am
It's not quite clear what you are after, but I'll take a stab at it. This would join the "starts" to the "ends" and allow for any "adjustments" in...
May 8, 2014 at 7:55 am
Viewing 5 posts - 1 through 5 (of 5 total)