Viewing 5 posts - 1 through 5 (of 5 total)
Thanks a lot Phil.
I shall try to work it out.
May 11, 2012 at 4:43 am
Unfortunately neither is an option. Could this be made by using the script component?
If so can please provide example code?
Thanks a lot
May 11, 2012 at 1:50 am
Hi Bob
Try the following...
select distinct(a.client)/*,a.group_cx*/ from testtable a,testtable b
where a.group_cx = b.group_cx
order by /*a.group_cx,*/a.client
The commented parts of the query are for you to check the correctness of your results
I hope...
February 23, 2006 at 1:46 am
Viewing 5 posts - 1 through 5 (of 5 total)