A EVA data model creates huge problems for those who are unwise enough to fall into the trap: No data integrity on data types, no referential integrity, no way to...

Yes, but 1900-01-01 is not good for the code I posted, because dates earlier than 1900-01-01 would return a negative modulus.

Since there is no SQL Server datetime before 1753-01-01, there is...

If you use PKZIP 5 or later, which has been out for 3 or 4 years, there is no limit on the size of the compressed files, and I have...

If you do it correctly, you should be able to move the database with only a few minutes of downtime.

1. Backup the database and copy the backup to the new...

This will give the time as an offset from midnight on 1900-1-1, the SQL Server zero day.

-- Subtract Date from Datetime to get Time on 1900-01-01
selectMyTime = MyDate-dateadd(dd,datediff(dd,0,MyDate),0)
from
( Select MyDate...

I guess I just know because it is the very first date that SQL Server supports, and I only had to look it up one time.

In any case, DATENAME(dw,'17530101') would be...

Try this function:

drop function fn_Last_Workday
go
create function fn_Last_Workday
(@start_day datetime,
@work_days int)
returns datetime
as
begin

declare @end_day datetime
declare @prior_workday datetime
declare @weeks  int
declare @remaining_days int

-- Return null if input parameters are invalid
if @start_day is null or @work_days is null or @work_days < 1
begin...

The function you posted is a scalar function, which means it can only return a single value.

If you want it to return more than one value, it will have to...

That is the point of the code I posted.  Since it doesn't use the DATEPART function, the setting of DATEFIRST has no effect on it.

It finds the day of the week...

I have a PC XT with a 20 MB hard drive and twin 5.25 floppy drives.

I don't understand what the problem you are trying to solve is.

Please explain and give examples.

The value that datepart(DW,MyDate) returns depends on the setting of datefirst.

This code will always return a value of 0 for Monday, 1 for Tuesday,...,  6 for Sunday, no matter what...

CREATE function GetRespondentFinal(
  @RespondentID  int,
  @SurveyInstanceID int)
returns int
as
begin
declare @xfinal int;
set @xfinal=null;

select  @xfinal=max(mfinal) from (
 select  MAX(sie.Final) mfinal
 from EventLog el, surveyInstanceEvents sie
 where el.respondentid = @respondentid
   and el.eventID = sie.eventID
   and sie.SurveyInstanceID =...

What is it that you want help with.  Creating a table?  Calculating the distance?  Something else?

This doesn't really seem to be a T-SQL question.