Viewing 10 posts - 1 through 10 (of 10 total)
Thanks Sarah,
How can I aggregate the distinct values only?
For example said person may appear multiple times per week, but how do I count them only once?
September 28, 2015 at 8:16 am
I guess there is no way of resolving this?
September 28, 2015 at 6:53 am
Looks like my colleague and I have sorted it 🙂
April 23, 2015 at 4:29 am
Thanks for this David,
Much appreciated
I will learn from this so that in future the expressions make more sense 🙂
March 11, 2015 at 8:31 am
Thanks for replying, basically if today is a Friday then show the data for Saturday, Sunday, Monday, if it's not a Friday show the data for the following day based...
March 11, 2015 at 7:42 am
Thank you for your help guys
It works 🙂
March 9, 2015 at 7:08 am
Appreciate it, thank you
February 23, 2015 at 4:20 pm
Appreciate you helping me here so it would be 28/01/2015 - 24/02/2015
The 24/2/2015 because the last 3 working days of the month are the cut off.
February 23, 2015 at 4:10 pm
So basically if the first day of the current month was a Sunday, I would want to capture everything from the Wednesday
If the first day of the next month was...
February 23, 2015 at 3:47 pm
Thanks for the replies guys, unfortunately we don't have access rights to create stored procedures (we as the reporting team are subservient to the IT team/database administrators).
I will also be...
February 23, 2015 at 3:33 pm
Viewing 10 posts - 1 through 10 (of 10 total)