Viewing 15 posts - 76 through 90 (of 10,144 total)
But this one doesn't return NULL, so a bit puzzling to me
SELECT CHOOSE((CAST(T.[Rand]* 10 AS INT))%3.00 + 1, 'one', 'two', 'three') Choice,
...
October 15, 2019 at 7:12 am
But this one doesn't return NULL, so a bit puzzling to me
SELECT CHOOSE((CAST(T.[Rand]* 10 AS INT))%3.00 + 1, 'one', 'two', 'three') Choice,
...
October 14, 2019 at 1:17 pm
August 5, 2019 at 8:06 am
Comments posted to this topic are about the item Making Good Use of SQL Server Auditing.
The link is to a Tony Davis article about Data Compression. [ Now...
July 25, 2019 at 10:08 am
Your script contains two queries, do you know how much of the total execution time each one takes?
Can you provide an execution plan for each of them, as a .sqlplan...
July 3, 2019 at 10:54 am
So, I don't want to argue through all this. We had a number of things, not just management, that pushed a release. Quite a few of the items wouldn't...
July 1, 2019 at 2:03 pm
@itsrainman you've coded this:
WHERE
(i.[Despatch Date] IS NULL)
AND (i.[Cal Date] IS NULL)
AND (i.[Despatch to subcontractor] IS NOT NULL)
AND (i.[Return from Subcontractor] IS...
June 20, 2019 at 2:40 pm
This was removed by the editor as SPAM
June 20, 2019 at 2:37 pm
Hi Mike
One of our solutions here uses a snapshot of a replicated database to replace a backup/restore process which used to take hours (about 12 of them). We don't talk...
June 20, 2019 at 12:40 pm
Have you looked into database snapshots for this? It would save you a heck of a lot of coding.
June 20, 2019 at 9:58 am
-- Work with what you can see.
-- Compare the columns from both sides, add to the matching columns list when you've figured out what's going on.
SELECT
T.[CustomerID],
T.[RelatedReferenceID],
T.[RelatedReferenceType],
T.[Due Date],
'#'...
June 17, 2019 at 12:52 pm
I am going to develop a dashboard to monitor various stats about our Testing Environments. One piece of information I want to pull is the date that a refresh...
June 14, 2019 at 3:27 pm
-- Use EOMONTH(H.startdate) instead of datename(MONTH,H.startdate), datepart(YEAR,H.startdate)
-- and remove h.Quantity from the GROUP BY
SELECT
RTRIM(COALESCE (E.PreferredName, E.FirstNames)) + ' ' + E.LastName AS [Name],
sum(H.Quantity) as [Hours],
datename(MONTH,x.YearMonth) as [month],
datepart(YEAR,x.YearMonth)...
June 12, 2019 at 7:33 am
How nice it is to see this again - a bunch of folks working the hell out of a problem to come up with their solutions, each one faster and...
June 3, 2019 at 1:09 pm
This looks about right, and if it is, then the start and end dates can be calculated.
;WITH SampleDates AS (
SELECT * FROM (VALUES
(GETDATE()+0),
('2019-01-26'),
('2019-01-27'),
('2019-01-28'),
('2019-01-29'),
('2019-01-30'),
('2019-01-31'),
('2019-02-01'),
('2019-02-23'),
('2019-02-24'),
('2019-02-25'),
('2019-02-26'),
('2019-03-23'),
('2019-03-24'),
('2019-03-25')
) d (thedate)
)
SELECT
thedate,
z.RealStartDate,
RealEndDate...
May 31, 2019 at 12:38 pm
Viewing 15 posts - 76 through 90 (of 10,144 total)