Try something like this...

DECLARE @data varchar(50)

DECLARE @Value int

DECLARE @Count int

DECLARE @val varchar(16)

SET @data = 'THIS IS A TEXT MESSATE SORRY IT...

george sibbald (6/3/2009)

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This gives the owner of the database

select suser_sname(sid),name from master..sysdatabases

just add the relevant where clause for a particular database

Retrieving who originally created the database (if different) I...

MarkusB,

Is it possible to achieve this through sql statement? Like sys.databases some thing like ....

---

Thanks you very much MarkusB for your quick info. 🙂

DECLARE @ExpDate int

DECLARE @CurrentDate NVARCHAR(180)

DECLARE @TimeElapsed NVARCHAR(180) -- 'hh:mm'

DECLARE @RemainingTime NVARCHAR(180)

SET @ExpDate = 13

SET @TimeElapsed = '06:00' -- 'hh:mm'

SET @CurrentDate = '2009-04-14 10:00:00.000'

SELECT @RemainingTime = -- Some Logic

My Result

---------

The result...

San (4/2/2009)

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You can try the below query as well.....There will be a better way...will check and revert back..

SELECT * FROM

(

SELECT

CASE WHEN (Row_Number() OVER (ORDER BY Q.QText)) > 1...

it works.

thanks mangal.

Thanks All for your valuable reply.

Yes Andrew, i have done that through dropping the foreign key and recreating the same.

But i am still doing, is there any other way...

😛 That i know. How can i achieve through...

Hi,

I got my it is happened. here i changed my sa password for my server.

When i right click and say create to ==> it shows me the old sa...

vikas bindra (1/22/2009)

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I had faced the same issue twice or thrice on my test server. That time I just restarted the SQL server service 🙂 (as it was a test...

vikas bindra (1/15/2009)

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Yes you can get away with these warnings. You will have to identity the objects that are generating these errors (as in the example AddEmployee SP) and then...

Thanks Vikas, RBarry for your quick reply.

I can understand now.

But is it possible to knock off that warning message also?

Because we are getting nearly 10 to 15 warning messages...

Thanks Jack for your valuable reply.

Here i was using NULLIF function. Using this i got the result. Please see the below code.

SELECT SCOPE_IDENTITY(),

ISNULL(NULLIF(Ques.value('Option1[1]','varchar(16)'),''),NULL) AS Option1,

...

DECLARE @HieLevel TABLE

(

HieID[uniqueidentifier],

HieLevel[tinyint],

ParentHieID[uniqueidentifier],

Levels[tinyint]

)

;WITH CTEHierLevel(fldHieID,fldHieLevel,fldParentHieID,Level)

AS

(

SELECT

fldHieID,

fldHieLevel,

fldParentHieID,

0 AS Level

FROM

tblHierachey

WHERE

fldHieID = @HieID

UNION ALL

SELECT

Client.fldHieID,

Client.fldHieLevel,

Client.fldParentHieID,

Level + 1

FROM

tblHierachey AS Client

INNER JOIN

CTEHieLevel AS CL

ON (Client.fldParentHieID = CL.fldHieID)

)

INSERT INTO @HierLevel (HieID,HieLevel,ParentHieID,Levels)

SELECT fldHieID,fldHieLevel,fldParentHieID,Level FROM CTEHierLevel order by level

/* Below...