Viewing 15 posts - 76 through 90 (of 159 total)
Gail - Just to be clear. This is what I'm trying.
C:\Program Files\Microsoft SQL Server\100\Tools\Binn>sqlcmd -E -S .\injest -A -Q"alter login [sys-admin] with name = sa"
October 4, 2011 at 3:15 pm
Fix the database ownership (set the db owner to sa) then repair the installation or reinstall the patch.
How can I fix the DB ownership if I cannot log in to...
October 4, 2011 at 2:50 pm
C:\Program Files\Microsoft SQL Server\100\Tools\Binn>sqlcmd -E -S .\injest -A
HResult 0x274D, Level 16, State 1
TCP Provider: No connection could be made because the target machine actively refused it.
Sqlcmd: Error: Microsoft SQL Server...
October 4, 2011 at 2:38 pm
Yes but in order to fix the DB owner I need to utilize sqlcmd.
sqlcmd -E -S .\myinstance -A
This part is failing. With this failing I can not...
October 4, 2011 at 2:32 pm
This is the named instance. I am running that from within the directory.
October 4, 2011 at 2:19 pm
I attempted to use the following
sqlcmd -E -A -Q"alter login [sys-admin] with name = sa"
It not making the connection to the SQL instance.
October 4, 2011 at 1:55 pm
I attempted to use the following
sqlcmd -E -A -Q"alter login [sys-admin] with name = sa"
It not making the connection to the SQL instance.
October 4, 2011 at 1:54 pm
Yes. I also went into the directory of the instance and double clicked the sqlcmd icon. I get a black screen then just disappears. I really appreciate...
October 4, 2011 at 1:42 pm
The net start command worked fine with the aforementioned switches but when I attempt to start sqlcmd it does not start. It acts like it doesn't exist.
C:\Program Files\Microsoft SQL...
October 4, 2011 at 1:25 pm
sqlcmd does not start for the 2008 instance. starts fine for the 2005 instance. is there anywhere I should check to see why this is not starting?
October 4, 2011 at 1:15 pm
Let me give it a shot. Thanks! I'll update in a few.
October 4, 2011 at 12:55 pm
The problem why I can't use the Pivot function requires the value to be an aggregate function..these are strings.
January 12, 2011 at 8:14 pm
The issue is the code needs to be dynamic as it relates to column 2 (values 64, 65 in this example)
Thanks for all your help!
January 12, 2011 at 5:29 pm
My apologies, I didn't have that information either. Thank you for the reply.
January 12, 2011 at 5:05 pm
Viewing 15 posts - 76 through 90 (of 159 total)