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Hi,
Thanks for your reply.
But it’s not division by zero error. I have handled that in code as follows:
Public Function DivisionFunction(ByVal Value_1 AS Decimal, Value_2 AS Decimal) AS Decimal
...
August 23, 2013 at 7:16 am
#1644396
Thanks for the code. It really useful.
Can you please explain the logic, so it will be easy to understand how it works.
When @days are less than 0 you have...
February 13, 2012 at 12:19 am
#1446103