Viewing 9 posts - 16 through 24 (of 24 total)
Whether we not concanate the two variable like
@Var1 + @Var2 ??
February 29, 2008 at 3:15 am
Hi,
Can you please check your query one more time, as it seems not right.
As the query itself will return 0 records.
select A.Column1, B.Column1, count(A.Column1) as Frequency
,sum(B.Column2-A.Column2) as Difference
from TEST_TABLE 1...
February 18, 2008 at 10:55 pm
Hi
I find a script which also get the default constraints.
This script I already added to my blog.
http://matespoint.blogspot.com
Thanks.
February 18, 2008 at 10:47 am
Hi,
Colud you please check you column values.
If it containings null values, while counting null values the query will not count it as a record , but while count(*) it will...
February 17, 2008 at 11:23 pm
Your query looks great!!
After this article I tried here and there but colud not get a compact solution, however I get a query to get all the constraints for a...
February 14, 2008 at 10:43 pm
I am confused with this question which somewhere says it takes the default schema if you dont provide one.
Please check http://msdn2.microsoft.com/en-us/library/ms177544.aspx
February 12, 2008 at 11:20 pm
I could not understand this question clearly.
May be someone please elaborate this.
February 12, 2008 at 11:06 pm
Nice twisted question, people had to think once again, i get it wrong although i was knowing that no middle join is there, but do not beyond that it can...
December 28, 2007 at 4:24 am
It just doing simple mathmetical expression,
For ex -
declare @i int
select @i = -5
select @i*@i
Answer = 25
declare @i int
select @i = 5
select @i*-@i
Answer = -25
declare @i int
select @i = 5
select...
December 28, 2007 at 3:28 am
Viewing 9 posts - 16 through 24 (of 24 total)