Viewing 6 posts - 1 through 6 (of 6 total)
ChrisM
the problem simply stated is to find a phrase in the db and return it's weight.
If the phrase I'm looking for contains extra words, is missing words or both, it makes...
August 14, 2007 at 1:32 pm
Chris, thanks for your response. I initial did a similar thing, then came up with this...
declare @w0 varchar(32)
declare @w1 varchar(32)
declare @w2 varchar(32)
declare @w3 varchar(32)
declare @w4 varchar(32)
declare...
August 14, 2007 at 11:56 am
Chris, thanks for your response. I initial did a similar thing, then came up with this...
declare @w0 varchar(32)
declare @w1 varchar(32)
declare @w2 varchar(32)
declare @w3 varchar(32)
declare @w4 varchar(32)
declare...
August 14, 2007 at 11:53 am
Hey thanks...your example below works great.
select distinct a1 , a2 from a
join (select distinct b1 , b2 from b ) as B
on B.b1 = A.a1
and b.b2 = A.a2
join (select distinct...
August 10, 2007 at 10:08 am
If an inner join has no rows won't the entire query fail?
August 10, 2007 at 9:43 am
Right, we're trying to find the common elements. In an intersection it's always possible the one or more tables won't match anything in the other tables. If that's the case...
August 10, 2007 at 9:26 am
Viewing 6 posts - 1 through 6 (of 6 total)