March 8, 2013 at 5:02 am
Hi,
Thanks for your help in advance, working with XML nodes for the first time and finding it frustrating. I am trying to build a relational table from some xml. setting each xml level to a new column in a table.
CREATE TABLE ClientInfo
(
ID INT PRIMARY KEY IDENTITY,
XMLInfo XML
);
INSERT INTO ClientInfo (XMLInfo)
VALUES
(
N'<?xml version="1.0" ?>
<Root>
<key>29</key>
<children>
<key>500</key>
<children>
<key>3000</key>
<children>
<key>70000</key>
</children>
</children>
</children>
<key>50</key>
<children>
<key>600</key>
<children>
<key>3600</key>
<children>
<key>9862</key>
</children>
<children>
<key>9863</key>
</children>
<children>
<key>9864</key>
</children>
</children>
</children>
<key>70</key>
<children>
<key>900</key>
<children>
<key>3700</key>
<children>
<key>7862</key>
</children>
<children>
<key>6863</key>
</children>
<children>
<key>5864</key>
</children>
</children>
<children>
<key>5400</key>
<children>
<key>7892</key>
</children>
<children>
<key>6563</key>
</children>
<children>
<key>5464</key>
</children>
</children>
</children>
</Root>
');
select * from [dbo].[ClientInfo]
SELECT
aref.value('(key/text())[1]', 'varchar(50)') as Column1,
bref.value('(key/text())[1]', 'varchar(50)') as Column2,
cref.value('(key/text())[1]', 'varchar(50)') as Column3,
dref.value('(key/text())[1]', 'varchar(50)') as Column4
FROM
ClientInfo CROSS APPLY
XmlInfo.nodes('//Root') AS Level1(aref) CROSS APPLY
aref.nodes('children') AS Level2(bref) CROSS APPLY
bref.nodes('children') AS Level3(cref) CROSS APPLY
cref.nodes('children') AS Level4(dref)
GO
When I run this query column 1 just has the first ID in this case 29 ? I would very much like it to report the other key's adjacent to their relevant children keys. Why is this not working for me.
Any useful material you can forward on would be gratefully appreciated.
Many Thanks,
Oliver
March 9, 2013 at 6:54 pm
Your xml format is not very well organized. Keys and children are not in any relation except positional, so it is almost impossible to relate them.
You should make children of the key to appear WITHING the parent key, not side by side.
Closest I could get is:
declare @ClientInfo xml =
N'<?xml version="1.0" ?>
<Root>
<key>29</key>
<children>
<key>500</key>
<children>
<key>3000</key>
<children>
<key>70000</key>
</children>
</children>
</children>
<key>50</key>
<children>
<key>600</key>
<children>
<key>3600</key>
<children>
<key>9862</key>
</children>
<children>
<key>9863</key>
</children>
<children>
<key>9864</key>
</children>
</children>
</children>
<key>70</key>
<children>
<key>900</key>
<children>
<key>3700</key>
<children>
<key>7862</key>
</children>
<children>
<key>6863</key>
</children>
<children>
<key>5864</key>
</children>
</children>
<children>
<key>5400</key>
<children>
<key>7892</key>
</children>
<children>
<key>6563</key>
</children>
<children>
<key>5464</key>
</children>
</children>
</children>
</Root>
'
SELECT
ParentID = c.x.value('../key[1]', 'int'),
ChildID = c.x.value('key[1]', 'int')
FROM @ClientInfo.nodes('//children') c(x) -- "//children" means "children nodes at all levels"
GO
The result is:
ParentID ChildID
----------- -----------
29 500
500 3000
3000 70000
29 600
600 3600
3600 9862
3600 9863
3600 9864
29 900
900 3700
3700 7862
3700 6863
3700 5864
900 5400
5400 7892
5400 6563
5400 5464
(17 row(s) affected)
If you change xml structure as suggested, similar construction would work perfectly.
Since preceding-sibling is not supported by sql2008, you could look into >> and << xml operators that I'm not very familiar with.
Some examples are here:
and here
March 11, 2013 at 2:25 am
Many Thanks for your help, sorry about the poorly constructed xml. I will have a look at the links you passed on.
Thanks again,
Oliver
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