October 16, 2017 at 9:47 am
Hi guys,
Can you help with the code below.
Update [Branch]
right join [Addresses] on [Branch].reference= [Addresses].ID
Set [Branch] Addresses 1 =Addresses.Addresses1
[Branch] Addresses 2 = Addresses.Addresses2
[Branch] Addresses 3 =Addresses.Addresses3
[Branch] Addresses 4 =Addresses.Addresses4
[Branch] PostCode =Addresses.postcode
[Branch] Fax =Addresses.FaxAddresses
[Branch] Number = number
the error message is the multi part identifier could not be bound
October 16, 2017 at 9:57 am
Please check the syntax of the UPDATE statement. The JOINs go at the end, after the assignments, and you need a FROM.
John
October 16, 2017 at 10:07 am
adan950 - Monday, October 16, 2017 9:47 AMHi guys,Can you help with the code below.
Update [Branch]
right join [Addresses] on [Branch].reference= [Addresses].ID
Set [Branch] Addresses 1 =Addresses.Addresses1
[Branch] Addresses 2 = Addresses.Addresses2
[Branch] Addresses 3 =Addresses.Addresses3
[Branch] Addresses 4 =Addresses.Addresses4
[Branch] PostCode =Addresses.postcode
[Branch] Fax =Addresses.FaxAddresses
[Branch] Number = numberthe error message is the multi part identifier could not be bound
Something like this (not tested):
UPDATE [br] SET
[Addresses 1] = [a].[Addresses1]
[Addresses 2] = [a].[Addresses2]
[Addresses 3] = [a].[Addresses3]
[Addresses 4] = [a].[Addresses4]
[PostCode] = [a].[postcode]
[Fax] = [a].[FaxAddresses]
[Number] = [a].[number] -- guessing at the alias needed on this line
FROM
[Branch] AS [br]
RIGHT OUTER JOIN [Addresses] AS [a]
ON [br].[reference] = [a].[ID];
October 16, 2017 at 10:16 am
thanks guys. it works.
October 17, 2017 at 1:48 am
Is there any reason why you're using a RIGHT OUTER JOIN? Updating the outer table of that join means you're going to be attempting to update rows that don't exist. Either you're going to get an error, or those rows are just going to be ignored. You should verify that an inner join gives the same results, and use that instead - it will make it much easier for anyone else (or your future else) who tries to understand the query!
John
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