Using a column name in a COUNT function

  • Comments posted to this topic are about the item Using a column name in a COUNT function

    ATBCharles Kincaid

  • That is well-known behavior of the COUNT(), but the question I have is this: What makes you think that COUNT(1) in any way superior to CONT(*)?

  • Hi,

    Why not use

    select p.[rows] from sys.partitions p

    where p.index_id in (0,1) and p.object_id = object_id('[schema].[TableName]')

    to replace count(1)?

    You already have the count for every table in sys.partitions view.

    Regards,

    IgorMi

    Igor Micev,My blog: www.igormicev.com

  • According to MS sys.partitions.rows "Indicates the approximate number of rows in this partition"

    http://technet.microsoft.com/en-us/library/ms175012.aspx

  • Count(*) doesn't load the entire table. It uses the index to return count.

  • danielfountain (10/15/2013)


    According to MS sys.partitions.rows "Indicates the approximate number of rows in this partition"

    http://technet.microsoft.com/en-us/library/ms175012.aspx

    Hi,

    Microsoft recommends to use the new dynamic views instead of some deprecated for future use

    The same result can be obtained by using this dynamic view as well

    select i.rowcnt from sys.sysindexes i where i.id = OBJECT_ID('[schema].[TableName]')

    and i.indid = 1

    I often use sys.partitions and it always gives out the same result as count(1). If the maintenance of the indexes is regularly done than that info is exact. However, a good remark of you, thanks.

    Regards,

    IgorMi

    Igor Micev,My blog: www.igormicev.com

  • The best way I've found for using COUNT(MyCol) is to use either the identity column or the primary key column. That way there are no NULL results to worry about.

    SELECT COUNT(NameID) FROM CountTestSET ANSI_NULLS ON;

    SET QUOTED_IDENTIFIER ON;

    IF EXISTS (SELECT object_id

    FROM sys.objects

    WHERE object_id = OBJECT_ID(N'[dbo].[CountTest]')

    AND type in (N'U')

    )

    DROP TABLE dbo.[CountTest];

    CREATE TABLE dbo.[CountTest]([NameID] INT NOT NULL IDENTITY(1,1),

    [Name] [nvarchar](max)

    );

    INSERT INTO dbo.[CountTest] ([Name]) VALUES('Sally');

    INSERT INTO dbo.[CountTest] ([Name]) VALUES(NULL);

    INSERT INTO dbo.[CountTest] ([Name]) VALUES('Mary');

    INSERT INTO dbo.[CountTest] ([Name]) VALUES('Jane');

    INSERT INTO dbo.[CountTest] ([Name]) VALUES(NULL);

    INSERT INTO dbo.[CountTest] ([Name]) VALUES('Bob');

    INSERT INTO dbo.[CountTest] ([Name]) VALUES('Tom');

    INSERT INTO dbo.[CountTest] ([Name]) VALUES(NULL);

    SELECT COUNT(NameID) FROM dbo.CountTest; --Gives count of 8

    SELECT COUNT(Name) FROM dbo.CountTest; --Gives count of 5

    DROP TABLE dbo.CountTest;

    Brandie Tarvin, MCITP Database AdministratorLiveJournal Blog: http://brandietarvin.livejournal.com/[/url]On LinkedIn!, Google+, and Twitter.Freelance Writer: ShadowrunLatchkeys: Nevermore, Latchkeys: The Bootleg War, and Latchkeys: Roscoes in the Night are now available on Nook and Kindle.

  • hi, I usually have the following scenario: I have to count the distincts names

    for this I use:

    SELECT COUNT(distinct name) AS [COUNT distinct] FROM [CountTest];

  • ...This can produce some surprising results. This is because of the way that COUNT() works...

    Why the surprise if COUNT exactly does what is described in e.g. Technet?

  • You know that doing COUNT(*) on a table with a lot of columns and a lot of rows can take a lot of time and memory

    There is virtually no difference between SELECT(*) and SELECT(1) - the execution plans are identical, and each will produce the same number of logical reads.

    ______________________________________________________________________________Never argue with an idiot; Theyll drag you down to their level and beat you with experience

  • MyDoggieJessie (10/15/2013)


    You know that doing COUNT(*) on a table with a lot of columns and a lot of rows can take a lot of time and memory

    There is virtually no difference between SELECT(*) and SELECT(1) - the execution plans are identical, and each will produce the same number of logical reads.

    +1

  • I had learned to count on the primary key column, count(RecordID) as NumberOfRecords. However, the suggestion below to query the system tables seems to be an even better solution.

  • Interesting results on the execution plan. All plans but the COUNT() on Name came backup with only an expected 9B in the row size. The Name count came back much bigger (and off of what the results were).

    Here are my statements:

    SELECT COUNT(NameID) FROM dbo.CountTest;

    SELECT COUNT(Name) FROM dbo.CountTest;

    SELECT COUNT(*) FROM dbo.CountTest;

    SELECT COUNT(1) FROM dbo.CountTest;

    Attached is the execution plans. Identical in every way except for the selecting on the name.

    Brandie Tarvin, MCITP Database AdministratorLiveJournal Blog: http://brandietarvin.livejournal.com/[/url]On LinkedIn!, Google+, and Twitter.Freelance Writer: ShadowrunLatchkeys: Nevermore, Latchkeys: The Bootleg War, and Latchkeys: Roscoes in the Night are now available on Nook and Kindle.

  • I've been known to use "SELECT COUNT(*) from SomeTable with (INDEX=1)" so that I DO load the entire table.

    Generally this would only be in a situation where I'm doing raw performance testing.

  • MyDoggieJessie (10/15/2013)


    You know that doing COUNT(*) on a table with a lot of columns and a lot of rows can take a lot of time and memory

    There is virtually no difference between SELECT(*) and SELECT(1) - the execution plans are identical, and each will produce the same number of logical reads.

    That's true, however SELECT * returns all the fields to the output, unlike SELECT 1, thus flooding the buffer with bytes of unnecessary data. That is not the case with COUNT(*) and COUNT(1) though. These are absolutely identical in all aspects, as far as I know.

    Please correct me if I am wrong - I would love to learn if there is a difference.

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