June 13, 2012 at 8:47 pm
Hello,
I want the ORDER BY for the below SQL as to display NONE in the first row and then the remaining values.
IF OBJECT_ID('TempDb..#Temp1') IS NOT NULL
DROP TABLE #Temp1
CREATE TABLE #Temp1(SourceA varchar(5))
INSERT INTO #Temp1
VALUES
('A')
,('B')
,('C')
,('D')
,('D')
,('E')
,('F')
,('G')
,('M')
,('N')
,('N')
,('N')
,('W')
,('Y')
,('Z')
SELECT * FROM #Temp1
UNION
SELECT ISNULL(NULL,'NONE') AS 'SourceA'
DROP TABLE #Temp1
OUTPUT as:
NONE
A
B
C
D
E
F
G
M
N
W
Y
Z
Thanks in advance!
June 13, 2012 at 9:17 pm
This?
; WITH CTE AS
(
SELECT DISTINCT SourceA
FROM #Temp1 T
UNION
SELECT 'NONE' AS 'SourceA'
)
SELECT *
FROM CTE C
ORDER BY CASE WHEN C.SourceA = 'NONE' THEN 1 ELSE 2 END , C.SourceA
June 13, 2012 at 10:24 pm
Or this?
SELECT CASE WHEN SourceA IS NULL THEN 'NONE' ELSE SourceA END
FROM #Temp1
GROUP BY SourceA WITH ROLLUP
ORDER BY SourceA
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My advice:
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[url url=http://www.sqlservercentral.com/articles/St
June 13, 2012 at 10:42 pm
Thanks All.
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