December 14, 2013 at 11:14 am
Comments posted to this topic are about the item T-SQL Arithmetic and Geometric Sequence (Series)
December 14, 2013 at 11:22 am
Somewhere your algebra 2 teacher is smiling......
I wonder what the performance difference would be if these operations were done in the CLR vs T-SQL:
a. In 2008
b. In 2008 R2
c. In 2012
d. In 2014
Would the difference be way less if the T-SQL operation was performed by natively compiled stored procedures accessing an in-memory table?
December 14, 2013 at 3:13 pm
sneumersky (12/14/2013)
Somewhere your algebra 2 teacher is smiling......I wonder what the performance difference would be if these operations were done in the CLR vs T-SQL:
a. In 2008
b. In 2008 R2
c. In 2012
d. In 2014
Would the difference be way less if the T-SQL operation was performed by natively compiled stored procedures accessing an in-memory table?
Algebra 2? Actually we covered these formulas in 2nd grade :-P. As for the performance difference, it is faster (at least 50% (taking in to account memory, processors, etc.) in the CLR because of the compiled code. But here is a really good article and test scenario comparing T-SQL UDF vs. SQLCLR UDF. While the article focuses on splitting strings, it applies for any UDF process. By the way, we use Idera for all of our database (scripts included) performance measurements.
Just as an FYI, this was asked of me years ago for some students in the 3rd grade. Basically, all the formulas were in UDF's (so the code was "clean") and had a ASP.NET front-end. Other UDF formulas I added were Arithmetic Series Summing, Geometric Series Summing and Mathematical Series.
Anyway, I wanted to share an easy and fun QoTD.
December 15, 2013 at 10:19 pm
To be honest, it's too much of calculation,
To me finding a geometric sequence with bare hands is not that much easier, when it reach over 10th term it's going to a night mare,
so i just find the answer for arithmetic and tick it straight away, if there are more than two same answers for the arithmetic mean i would surely get stuck, seems bit lucky today? i got the answer Right
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December 16, 2013 at 12:32 am
As per the question, it was mentioned that "Developed and tested using SQL Server 2008 R2 SP2"; so why don`t we use the new features available from SQL Server 2008 onwards like follows:
declare @start float = 1,
@commonDiff float = 3,
@counter float = 0
print 'Begin';
while @counter < 200
begin
set @counter += 1
declare @currVal float = 0
Setting the Variable`s values in the same declaration is more efficient, easier, faster and it looks even better.
BTY; I tested it, got the same results.
Thanks & Best Regards,
Hany Helmy
SQL Server Database Consultant
December 16, 2013 at 2:00 am
a ) is missing in the line (at the end).
Then Ceiling((@start + (@commonDiff * (@counter -1))) * Power(10,1))/Power(10, 1
Otherwise a very nice example 🙂
Søren,
MCITP SQL 2008 (administration / programming), MCITP SQL 2005 (BI), MCT
December 16, 2013 at 2:29 am
Whoah whoah, it's Monday! Easy with the questions 😀
(seriously, nice question)
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December 16, 2013 at 2:49 am
Søren (12/16/2013)
a ) is missing in the line (at the end).
I'm most disappointed that there aren't already several pages of identical posts moaning about that and demanding that some points be given back 😉
I confess to getting it right by the same method as thava used - check the easy bit and ignore the hard bit!
December 16, 2013 at 3:37 am
It is not about getting points back or focusing on wrong things.
It is a good, funny and very interesting example and why not make it better by fixing the code?
Søren,
MCITP SQL 2008 (administration / programming), MCITP SQL 2005 (BI), MCT
December 16, 2013 at 4:48 am
Bit complicated.
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December 16, 2013 at 6:02 am
Søren (12/16/2013)
a ) is missing in the line (at the end).Then Ceiling((@start + (@commonDiff * (@counter -1))) * Power(10,1))/Power(10, 1
Otherwise a very nice example 🙂
Thanks for catching that. I really do not know how that got cut off???
Then Ceiling((@start + (@commonDiff * (@counter -1))) * Power(10,1))/Power(10, 1)
December 16, 2013 at 6:33 am
steve.jacobs (12/16/2013)
Søren (12/16/2013)
a ) is missing in the line (at the end).Then Ceiling((@start + (@commonDiff * (@counter -1))) * Power(10,1))/Power(10, 1
Otherwise a very nice example 🙂
Thanks for catching that. I really do not know how that got cut off???
Then Ceiling((@start + (@commonDiff * (@counter -1))) * Power(10,1))/Power(10, 1)
Yeah, the missing ) was inconvenient, but it was still a good question. Maybe I should read the question better next time. 🙂
December 16, 2013 at 6:42 am
Ed Wagner (12/16/2013)
steve.jacobs (12/16/2013)
Søren (12/16/2013)
a ) is missing in the line (at the end).Then Ceiling((@start + (@commonDiff * (@counter -1))) * Power(10,1))/Power(10, 1
Otherwise a very nice example 🙂
Thanks for catching that. I really do not know how that got cut off???
Then Ceiling((@start + (@commonDiff * (@counter -1))) * Power(10,1))/Power(10, 1)
Yeah, the missing ) was inconvenient, but it was still a good question. Maybe I should read the question better next time. 🙂
Ed, I do not know how it got cut off, but I have reached out to Steve so I can add the ")" to the end of the statement.
December 16, 2013 at 7:35 am
Since
Abs((@start + (@commonDiff * (@counter -1))) -
Round((@start + (@commonDiff * (@counter -1))), 1, 1)) * Power(10, 1) = 5
would never evaluate to true, the rest was easy enough for a Monday.
Thanks for the question.
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December 16, 2013 at 7:57 am
Koen Verbeeck (12/16/2013)
Whoah whoah, it's Monday! Easy with the questions 😀(seriously, nice question)
+1 I had to step away from this one and get some brain juices flowing before I walked through it. When I first looked at it I was like :doze: "Math?...Ooh..caffeine time".
Really great question!
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