^ : T-SQL

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^ : T-SQL

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DavidSimpson Hall of Fame Points: 3562 More actions · Answer 1

ronmoses (11/20/2009)
I got tripped up on the fact that the string didn't end with %. So I answered the question for 'Jo[^n]%' instead of 'Jo[^n]'. Oops.

Add me to this list. Read the question and answered too quickly. Missed the fact the % wasn't listed. :blink:

David

Steve Jones - SSC Editor SSC Guru Points: 736254 More actions · Answer 2

The answer, based on LIKE, is that you are looking for 3 character matches without the %.

So you have possible:

John

Jonathan

Jon

Joe

Jack

Of these, the 3 character ones are:

Jon

Joe

Of those, the pattern "JO[^n]" is matched only by Joe. Jon has an "n" in the third position and the caret (^) means do not match.

If we had added the % at the end, "JO[^n]%", then "John" would have matched as well. "Jonathan would not have matched with an "n" in the third position.

Elly Odell SSC Enthusiast Points: 172 More actions · Answer 3

Elly Odell

SSC Enthusiast

Points: 172

November 20, 2009 at 12:00 pm

#1082406

Thank You.:-)

meilu7720 Newbie Points: 6 More actions · Answer 4

Nice explanation. Thanks

Steve Jones - Editor (11/20/2009)
The answer, based on LIKE, is that you are looking for 3 character matches without the %.
So you have possible:
John
Jonathan
Jon
Joe
Jack
Of these, the 3 character ones are:
Jon
Joe
Of those, the pattern "JO[^n]" is matched only by Joe. Jon has an "n" in the third position and the caret (^) means do not match.
If we had added the % at the end, "JO[^n]%", then "John" would have matched as well. "Jonathan would not have matched with an "n" in the third position.

david.wright-948385 SSCarpal Tunnel Points: 4041 More actions · Answer 5

I'm pretty sure the '^' character is a caret, not a carot 🙂

vignesh 38804 Old Hand Points: 338 More actions · Answer 6

Try this

select * from @table where [name] like 'Jo_'

TomThomson SSC Guru Points: 104773 More actions · Answer 7

Steve Jones - Editor (11/20/2009)
The answer, based on LIKE, is that you are looking for 3 character matches without the %.
So you have possible:
John
Jonathan
Jon
Joe
Jack
Of these, the 3 character ones are:
Jon
Joe
Of those, the pattern "JO[^n]" is matched only by Joe. Jon has an "n" in the third position and the caret (^) means do not match.
If we had added the % at the end, "JO[^n]%", then "John" would have matched as well. "Jonathan would not have matched with an "n" in the third position.

Wouldn't it have been nice if the answer's explanation had given this detail, or at the very least made the point that [^n] matches only a single character? The imaginary "%" on the end of the pattern mentioned bin a couple of comments describes exactly where I went wrong, don't know why because I should be on top of this given how much I've used it) but the explanations should surely try a bit harder to educate.

Tom