April 10, 2009 at 3:21 am
hi i am new bie to birt report wen i am giving query statement it is giving null values in two fields how to replace null values with strings in select statementcan any one help me........
April 10, 2009 at 3:31 am
Hi
If I've understood you correctly, you are wanting to replace a NULL value in a SELECT statement, try using ISNULL, e.g.
SELECT ISNULL( , 'string')
Have a look at IsNull in books online for more information.
Thanks
-Matt
April 10, 2009 at 3:43 am
hi matt thanx for ur reply but its not working iwill give u some idea about my table in my table adid, country, state ,city are the field names but in state and city i am getting null values can u please give me some code now
thanx
April 10, 2009 at 3:50 am
Hi
My mistake I missed some info out of my previous example.
SELECT T1.ADID, T1.COUNTRY, ISNULL(T1.STATE,'the text you want instead of NULL')
FROM yourtable AS T1
April 10, 2009 at 4:04 am
Hi
matt its giving same result i.e., it is giving same null value and in the field name state is replacing with UNNAMED_3 any more information regarding this
Thanx
April 10, 2009 at 4:10 am
Hi
Can you reply with a sample of your code? What application are you writing this in?
Thanks
-Matt
April 10, 2009 at 4:21 am
Hi
i am developing birt reports from mysql database wen i am retriving data from the table SELECT advid , country , state, city
FROM T1
some of my column values of state and country are giving null values now i want to change these null values with string values i have replaced ur code but it is giving the same null values result.
Thanx
April 10, 2009 at 4:51 am
bvinay57 (4/10/2009)
Hii am developing birt reports from mysql database wen i am retriving data from the table SELECT advid , country , state, city
FROM T1
some of my column values of state and country are giving null values now i want to change these null values with string values i have replaced ur code but it is giving the same null values result.
Thanx
Try out following examples:
root@host# mysql -u root -p password;
Enter password:*******
mysql> use TUTORIALS;
Database changed
mysql> create table tcount_tbl
-> (
-> tutorial_author varchar(40) NOT NULL,
-> tutorial_count INT
-> );
Query OK, 0 rows affected (0.05 sec)
mysql> INSERT INTO tcount_tbl
-> (tutorial_author, tutorial_count) values ('mahran', 20);
mysql> INSERT INTO tcount_tbl
-> (tutorial_author, tutorial_count) values ('mahnaz', NULL);
mysql> INSERT INTO tcount_tbl
-> (tutorial_author, tutorial_count) values ('Jen', NULL);
mysql> INSERT INTO tcount_tbl
-> (tutorial_author, tutorial_count) values ('Gill', 20);
mysql> SELECT * from tcount_tbl;
+-----------------+----------------+
| tutorial_author | tutorial_count |
+-----------------+----------------+
| mahran | 20 |
| mahnaz | NULL |
| Jen | NULL |
| Gill | 20 |
+-----------------+----------------+
4 rows in set (0.00 sec)
mysql>
You can see that = and != do not work with NULL values as follows:
mysql> SELECT * FROM tcount_tbl WHERE tutorial_count = NULL;
Empty set (0.00 sec)
mysql> SELECT * FROM tcount_tbl WHERE tutorial_count != NULL;
Empty set (0.01 sec)
To find records where the tutorial_count column is or is not NULL, the queries should be written like this:
mysql> SELECT * FROM tcount_tbl
-> WHERE tutorial_count IS NULL;
+-----------------+----------------+
| tutorial_author | tutorial_count |
+-----------------+----------------+
| mahnaz | NULL |
| Jen | NULL |
+-----------------+----------------+
2 rows in set (0.00 sec)
mysql> SELECT * from tcount_tbl
-> WHERE tutorial_count IS NOT NULL;
+-----------------+----------------+
| tutorial_author | tutorial_count |
+-----------------+----------------+
| mahran | 20 |
| Gill | 20 |
+-----------------+----------------+
2 rows in set (0.00 sec)
kshitij kumar
kshitij@krayknot.com
www.krayknot.com
April 10, 2009 at 5:21 am
Thanku krayknot for ur reply.
February 8, 2010 at 4:05 pm
Select COALESCE(T1.State, 'String') as state
from table1 as T1
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