returning only a portion of a textbox field
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Hello
I need to return only in my select the following value of the content of my field name CODPOST:
ex: 4520-169 FEIRA
i need to return only FEIRA
I can do that , i can use right(substring(codpost,1,char(13)), the ideal solution is to search for a determinate character to divide the string in this CHR(13).
Anyone could help me
Thanks and Merry Christmas for all the comunity
Luis Santos
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Have you looked into CHARINDEX and PATINDEX in BOL? I think that's what you are looking for.
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Your first solution looks fine to me, but this will find the character position of the (first occurrence of) space
declare @STR varchar(50), @pos int
set @STR = '4520-169 FEIRA'
set @pos = charindex(' ', @STR)
select @STR String, @pos SpacePosition
I am also intrigued as to the data held in a field called 'CODPOST' - sounds a bit fishy to me
The absence of evidence is not evidence of absence
- Martin Rees
The absence of consumable DDL, sample data and desired results is, however, evidence of the absence of my response
- Phil Parkin -
I'm not sure I completely understand your question, but see if this example helps:
DROP TABLE codPostTest
GO
CREATE TABLE codPostTest
(
id int IDENTITY(1,1)
, codpost varchar(20)
)
GO
SET NOCOUNT ON
INSERT codPostTest (codpost) VALUES ('4520-169 FEIRA')
INSERT codPostTest (codpost) VALUES ('4520-169 ANDY')
INSERT codPostTest (codpost) VALUES ('4520-169 BRIAN')
INSERT codPostTest (codpost) VALUES ('4520-169 STEVE')
INSERT codPostTest (codpost) VALUES ('4520-169')
INSERT codPostTest (codpost) VALUES ('4520-169 ')
SET NOCOUNT OFF
SELECT codpost
, CASE
WHEN CharIndex(' ', RTrim(codpost)) = 0 THEN codpost -- or possibly '' or NULL
ELSE Substring(codpost, CharIndex(' ', codpost) + 1, Len(codpost))
END AS codpostName
FROM codPostTest
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