Replacing a string when the value is found in a table

• Jani Lane

  SSC-Addicted

  Points: 430

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  May 1, 2013 at 11:29 pm

  #273537

  Hi guys,

  I'm trying to create a function where I can pass a string value that will be used for searching a table column and see if there is match, then replace that string partially when found like below:

  Passed string: "John Doe University"

  The column values from the table:

  SELECT LastName FROM ThisTable

  --------------------------------

  LastName

  ---------

  Cruz

  Patar

  Doe

  QuiJong

  Halal

  So if the search is succesful, I'll replace the string with empty string, then the value will be returned as:

  John University

  Hope it makes sense?

  Thanks

• Sergiy

  SSC Guru

  Points: 110208

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  May 2, 2013 at 1:09 am

  #1611801

  select @SearchString = REPLACE(@SearchString, LastName, '')

  FROM ThisTable

  select @SearchString

  _____________
  Code for TallyGenerator

• Steven Willis

  SSCrazy Eights

  Points: 9893

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  May 2, 2013 at 1:45 am

  #1611812

  Not exactly clear on what you are trying to accomplish, but my first instinct is to suggest the STUFF function. You can google it.

   

• Jani Lane

  SSC-Addicted

  Points: 430

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  May 2, 2013 at 3:20 pm

  #1612037

  Thanks guys, Sergiy's answer is exactly what I needed.

  Have a nice day.:-)

• kapil_kk

  SSC-Insane

  Points: 21316

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  May 3, 2013 at 3:21 am

  #1612115

  Sergiy (5/2/2013)

  ---

  select @SearchString = REPLACE(@SearchString, LastName, '')

  FROM ThisTable

  select @SearchString

  +1 🙂

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