May 30, 2014 at 1:14 am
How to replace all the characters in a string by specific character.
e.g. my string is '123123123'
the output I want is '#########'
i.e. replace every string based on its length with # characters.
the number of characters in my string '123123123' is 9
so I need an output with having 9 # i.e. '#########'
May 30, 2014 at 2:33 am
Hi there,
If it is a straight like for like replacement then this would work
update [mytable]
set [mycolumn] = '#########'
where len([mycolumn]) = 9
If the task is more complex then you will need to be using REPLACE or STUFF or SUBSTRING with CHARINDEX or any number of other methods.
To get better help read the link in my signature which discribes the method to post information.
May 30, 2014 at 3:00 am
This uses REPLICATE to replace each character in a string with '#':
CREATE TABLE #test(
TestvalueVARCHAR(60)
);
INSERT INTO #test(Testvalue)
VALUES('one'),
('long string'),
('slightly longer string than the previous one'),
('12121212');
SELECT * FROM #test;
UPDATE #test
SET Testvalue = REPLICATE('#',LEN(Testvalue));
SELECT *
FROM #test;
DROP TABLE #test;
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