Remove Decimals Without Rounding

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Remove Decimals Without Rounding

ted montoya

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Points: 499
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September 26, 2007 at 12:35 pm

#374824

How do I take a number like maybe 10.73 and remove the decimal place and making it a number like 1073. In other words I have to remove the decimal.
I need to do it using T-SQL
Thanks for any help
Ted

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Janet Keith-489067 Ten Centuries Points: 1052 More actions · Answer 1

declare @mynum decimal(10,2)

declare @mynum1 int

set @mynum = 10.73

select @mynum1 = @mynum * 100

print @mynum

print @mynum1

or

declare @mynum decimal(10,2)

set @mynum = 10.73

select cast(@mynum * 100 as int)

ted montoya SSC-Addicted Points: 499 More actions · Answer 2

Thanks for your prompt answer.

I was looking for something that would get rid of the decimal point

if the number was 10.73 or 10.733 or 10.7333 or 10.7

The decimal place being in any position

Thanks

Ted

Janet Keith-489067 Ten Centuries Points: 1052 More actions · Answer 3

what is the datatype of the field containing the decimal point?

If it's varchar you could:

declare @mynum varchar(20)

set @mynum = '10.7333'

select replace(@mynum,'.','')

ted montoya SSC-Addicted Points: 499 More actions · Answer 4

The field is numeric(5,4)

but you have something there.

would it be possible to move it to a char field and then apply the logic you gave me

Again, thank you so much for your generous help

Ted

Dinakar Nethi-176633 SSCarpal Tunnel Points: 4689 More actions · Answer 5

declare @i decimal(10,2)

Set @i = 1078.734

select (left(@i, Charindex('.', @i, 1) - 1 ))

******************
Dinakar Nethi
Life is short. Enjoy it.
******************

Jeff Moden SSC Guru Points: 1004339 More actions · Answer 6

Doesn't matter if it's varchar or not... your method still works...

declare @i decimal(10,2)

Set @i = 1078.734

PRINT REPLACE(@i,'.','')

--Jeff Moden

RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

Change is inevitable... Change for the better is not.

Helpful Links:
How to post code problems
How to Post Performance Problems
Create a Tally Function (fnTally)

ted montoya SSC-Addicted Points: 499 More actions · Answer 7

Thank you all for your quick responses

I finally made it work with your help

Ted

Jeff Moden SSC Guru Points: 1004339 More actions · Answer 8

Cool... but it's customary to thank folks by posting the code that you used to make it work 😉

--Jeff Moden

RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

Change is inevitable... Change for the better is not.

Helpful Links:
How to post code problems
How to Post Performance Problems
Create a Tally Function (fnTally)

Tomm Carr SSCertifiable Points: 5426 More actions · Answer 9

The problem with using the Replace string function is that 10.341 ends up as 1034100 if the numeric is defined with five places. If you want 10.342 to end up as 10341, 10.73 as 1073, 10.733 as 10733, 10.7333 as 107333 and 10.7 as 107, then the best way is to use numeric processes rather than string.

The only thing is, you have to define your working number to have enough places to the left to contain the entire value. So your example of storing 10.341 into a variable defined as decimal(5,4) is bogus--it only has one place to the left of the decimal point. So if your value is defined as "decimal(x,y)" then you have to declare a working variable as "decimal(x+y,y)" to contain the entire finished value.

declare @original decimal( 10, 5 ),

@Working decimal( 15, 5 ), -- 10 + 5 = 15

@Result decimal( 15, 0 ); -- Doesn't need scale, only precision

Set @original = 1078.734; -- This would be, say, an input parameter

-- First, make a copy into the working variable capable of handling it.

Set @Working = @original;

-- Now set up the loop

Set @Result = Floor( @Working );

While @Result < @Working

begin

Set @Working = @Working * 10;

Set @Result = floor( @Working );

end--while

select @Result as Result, @Working as Working;The loop executes one time through for each significant digit to the right of the decimal point -- in this example, three times. The result is 1078734 instead of 107873400.

As an aside, does anyone know how to get the old "<pre></pre>" formatting back? This code IFCode shortcut sucks. Sure, the code goes into a nice text field 🙂 but everything is double spaced. :angry:

Tomm Carr
--
Version Normal Form -- http://groups.google.com/group/vrdbms

chan_dwr SSC Rookie Points: 49 More actions · Answer 10

DECLARE @MYDECVAR DECIMAL

DECLARE @MYINTVAR INT

SET @MYDECVAR = 100.123

SET @MYINTVAR = CAST(@MYDECVAR AS INT)

SELECT @MYINTVAR

CHEERS 🙂

CHANDRA

Ninja's_RGR'us SSC Guru Points: 294069 More actions · Answer 11

DECLARE @MYDECVAR DECIMAL

DECLARE @MYINTVAR INT

SET @MYDECVAR = 100.123

SET @MYINTVAR = CAST(@MYDECVAR AS INT)

SELECT @MYINTVAR

This returns 100, not 100123 as it should.

Ninja's_RGR'us SSC Guru Points: 294069 More actions · Answer 12

This should do the trick... 100% of the time :

DECLARE @val DECIMAL (11,8)

SET @val = 100.10300100

SELECT REPLACE(RTRIM(LTRIM(REPLACE(REPLACE(CONVERT(VARCHAR(30), @val), '.', ''), '0', ' '))), ' ', '0')

SET @val = 0.01

SELECT REPLACE(RTRIM(LTRIM(REPLACE(REPLACE(CONVERT(VARCHAR(30), @val), '.', ''), '0', ' '))), ' ', '0')

SET @val = 1

SELECT REPLACE(RTRIM(LTRIM(REPLACE(REPLACE(CONVERT(VARCHAR(30), @val), '.', ''), '0', ' '))), ' ', '0')

SET @val = 0010.20301

SELECT REPLACE(RTRIM(LTRIM(REPLACE(REPLACE(CONVERT(VARCHAR(30), @val), '.', ''), '0', ' '))), ' ', '0')

Jeff Moden SSC Guru Points: 1004339 More actions · Answer 13

Why do you think you need the extra overhead of RTRIM/LTRIM when converting Decimal to Varchar?

--Jeff Moden

RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

Change is inevitable... Change for the better is not.

Helpful Links:
How to post code problems
How to Post Performance Problems
Create a Tally Function (fnTally)

Ninja's_RGR'us SSC Guru Points: 294069 More actions · Answer 14

For dropping leading and trailing 0s from the string. Maybe I just missed the problem altogether...

Must be having a bad day or something.