August 11, 2014 at 2:52 am
Hi
how do I do I pull out the first three chars of a column using a derived column. I need to pull out first 3 chars and use them at a later time in the code
August 11, 2014 at 2:56 am
You use the LEFT function.
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MCSE Business Intelligence - Microsoft Data Platform MVP
August 11, 2014 at 2:59 am
ok thanks
and if the string is not all the same length I will probably hit problems ?
August 11, 2014 at 3:11 am
ronan.healy (8/11/2014)
ok thanksand if the string is not all the same length I will probably hit problems ?
As long as the string is three or more characters, you should be fine.
The absence of evidence is not evidence of absence
- Martin Rees
The absence of consumable DDL, sample data and desired results is, however, evidence of the absence of my response
- Phil Parkin
August 11, 2014 at 3:16 am
I used this
Left(TaxLotDescription,3)
and its not working. I then looked into my string function and left is not there right is. why is that
August 11, 2014 at 3:16 am
Phil Parkin (8/11/2014)
ronan.healy (8/11/2014)
ok thanksand if the string is not all the same length I will probably hit problems ?
As long as the string is three or more characters, you should be fine.
Even if the string is shorter than three characters, it's not an issue. LEFT will just return the original string.
Need an answer? No, you need a question
My blog at https://sqlkover.com.
MCSE Business Intelligence - Microsoft Data Platform MVP
August 11, 2014 at 3:20 am
ronan.healy (8/11/2014)
I used thisLeft(TaxLotDescription,3)
and its not working. I then looked into my string function and left is not there right is. why is that
Ah, LEFT is probably introduced in a later version.
In that case, use SUBSTRING instead.
Need an answer? No, you need a question
My blog at https://sqlkover.com.
MCSE Business Intelligence - Microsoft Data Platform MVP
August 11, 2014 at 3:21 am
in ssis 2005 you need to use SUBSTRING(ColumnName,1,3)
August 11, 2014 at 3:30 am
thanks that worked
August 11, 2014 at 3:32 am
Use below example :
DECLARE @i TABLE( mychar VARCHAR(50)
,deriv as SUBSTRING(mychar,1,3) --Use this
,newderiv as left(mychar,3)); --Or use this
INSERT @i VALUES ('Steve'), ('Stephan'), ('Stephanie')
, ('Sterling'), ('Steppenwolf'),('Ab')
SELECT * FROM @i
Vimal LohaniSQL DBA | MCP (70-461,70-462)==============================The greatest barrier to success is the fear of failure ** Success is a journey not a destination**Think before you print, SAVE TREES, Protect Mother Nature
August 11, 2014 at 4:21 am
Koen Verbeeck (8/11/2014)
Phil Parkin (8/11/2014)
ronan.healy (8/11/2014)
ok thanksand if the string is not all the same length I will probably hit problems ?
As long as the string is three or more characters, you should be fine.
Even if the string is shorter than three characters, it's not an issue. LEFT will just return the original string.
Thanks for the correction!
The absence of evidence is not evidence of absence
- Martin Rees
The absence of consumable DDL, sample data and desired results is, however, evidence of the absence of my response
- Phil Parkin
August 17, 2014 at 10:39 pm
I didn't find any error with the code :
DECLARE @i TABLE( mychar VARCHAR(50)
,deriv as SUBSTRING(mychar,1,3) --Use this
,newderiv as left(mychar,3));--Or use this
INSERT @i VALUES ('Steve'), ('Stephan'), ('Stephanie')
, ('Sterling'), ('Steppenwolf'),('Ab'),('Abc')
SELECT * FROM @i
--RESULT :
(7 row(s) affected)
mychar deriv newderiv
-------------------------------------------------- ----- --------
Steve Ste Ste
Stephan Ste Ste
Stephanie Ste Ste
Sterling Ste Ste
Steppenwolf Ste Ste
Ab Ab Ab
Abc Abc Abc
(7 row(s) affected)
Vimal LohaniSQL DBA | MCP (70-461,70-462)==============================The greatest barrier to success is the fear of failure ** Success is a journey not a destination**Think before you print, SAVE TREES, Protect Mother Nature
October 31, 2014 at 6:51 pm
Vimal Lohani (8/17/2014)
I didn't find any error with the code :DECLARE @i TABLE( mychar VARCHAR(50)
,deriv as SUBSTRING(mychar,1,3) --Use this
,newderiv as left(mychar,3));--Or use this
INSERT @i VALUES ('Steve'), ('Stephan'), ('Stephanie')
, ('Sterling'), ('Steppenwolf'),('Ab'),('Abc')
SELECT * FROM @i
--RESULT :
(7 row(s) affected)
mychar deriv newderiv
-------------------------------------------------- ----- --------
Steve Ste Ste
Stephan Ste Ste
Stephanie Ste Ste
Sterling Ste Ste
Steppenwolf Ste Ste
Ab Ab Ab
Abc Abc Abc
(7 row(s) affected)
You're running the above script in management studio. The question deals with the derived column SSIS transformation (used inside a data flow task). I also dont have the LEFT function here in SSIS 2008 either. So it must have come later.
----------------------------------------------------
October 31, 2014 at 8:12 pm
MMartin1 (10/31/2014)
Vimal Lohani (8/17/2014)
I didn't find any error with the code :DECLARE @i TABLE( mychar VARCHAR(50)
,deriv as SUBSTRING(mychar,1,3) --Use this
,newderiv as left(mychar,3));--Or use this
INSERT @i VALUES ('Steve'), ('Stephan'), ('Stephanie')
, ('Sterling'), ('Steppenwolf'),('Ab'),('Abc')
SELECT * FROM @i
--RESULT :
(7 row(s) affected)
mychar deriv newderiv
-------------------------------------------------- ----- --------
Steve Ste Ste
Stephan Ste Ste
Stephanie Ste Ste
Sterling Ste Ste
Steppenwolf Ste Ste
Ab Ab Ab
Abc Abc Abc
(7 row(s) affected)
You're running the above script in management studio. The question deals with the derived column SSIS transformation (used inside a data flow task). I also dont have the LEFT function here in SSIS 2008 either. So it must have come later.
Please use substring.
Vimal LohaniSQL DBA | MCP (70-461,70-462)==============================The greatest barrier to success is the fear of failure ** Success is a journey not a destination**Think before you print, SAVE TREES, Protect Mother Nature
November 1, 2014 at 12:17 pm
MMartin1 (10/31/2014)
Vimal Lohani (8/17/2014)
I didn't find any error with the code :DECLARE @i TABLE( mychar VARCHAR(50)
,deriv as SUBSTRING(mychar,1,3) --Use this
,newderiv as left(mychar,3));--Or use this
INSERT @i VALUES ('Steve'), ('Stephan'), ('Stephanie')
, ('Sterling'), ('Steppenwolf'),('Ab'),('Abc')
SELECT * FROM @i
--RESULT :
(7 row(s) affected)
mychar deriv newderiv
-------------------------------------------------- ----- --------
Steve Ste Ste
Stephan Ste Ste
Stephanie Ste Ste
Sterling Ste Ste
Steppenwolf Ste Ste
Ab Ab Ab
Abc Abc Abc
(7 row(s) affected)
You're running the above script in management studio. The question deals with the derived column SSIS transformation (used inside a data flow task). I also dont have the LEFT function here in SSIS 2008 either. So it must have come later.
The LEFT string function is first found in SSIS 2012.
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