October 21, 2013 at 2:52 pm
Here's my simplified table...
Invoice_id
897456-0001
897456-0002
897456-0003
898657-0001
898657-0004
889977-0003
889978-0002
889978-0004
889979-0001
889979-0010
889995-0002
889995-0003
889995-0004
I want to write a script so that it returns the following results...
889977-0003
889978-0002
889978-0004
889995-0002
889995-0003
889995-0004
Basically the first 6 digits are the account number and the next 4 are the invoice numbers (after the hyphen). I don't want any results on an account number if the account number has an invoice of 0001. If the account has a 0002 or higher only, I want all invoice id's returned.
How would I approach this?
TIA,
John
October 21, 2013 at 2:58 pm
Use MAX
Group by the stuff before the dash.
CAST the stuff after the dash as a number, get MAX of it.
October 21, 2013 at 3:13 pm
SELECT invoice_id
FROM <YOURTABLE>
WHERE LEFT(invoice_id, 6) NOT IN
(
SELECT DISTINCT LEFT(invoice_id, 6)
FROM <YOURTABLE>
WHERE (RIGHT(invoice_id, 4) = '0001')
)
________________________________________________________________
you can lead a user to data....but you cannot make them think
and remember....every day is a school day
October 21, 2013 at 4:12 pm
Because I pulled the data into a temporary table from the main db, this script wasn't working. I figured out that because I took the data as is, the field was of type CHAR(20)...and it's not something mentioned in my original post so you wouldn't have known. When I changed your script to...
SELECT invoice_id
FROM <YOURTABLE>
WHERE LEFT(RTRIM(invoice_id), 6) NOT IN
(
SELECT DISTINCT LEFT(RTRIM(invoice_id), 6)
FROM <YOURTABLE>
WHERE (RIGHT(RTRIM(invoice_id), 4) = '0001')
)
...it worked beautifully.
Thanks for putting me on track with this.
October 21, 2013 at 6:27 pm
Illustrating what PietLinden suggested, which I like because it avoids the sort inherent in DISTINCT:
WITH SampleData AS
(
SELECT invoice_no
FROM
(
VALUES ('897456-0001')
,('897456-0002')
,('897456-0003')
,('898657-0001')
,('898657-0004')
,('889977-0003')
,('889978-0002')
,('889978-0004')
,('889979-0001')
,('889979-0010')
,('889995-0002')
,('889995-0003')
,('889995-0004')
) a (invoice_no)
)
SELECT invoice_no=MAX(invoice_no)
FROM SampleData
GROUP BY LEFT(invoice_no, 6);
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My advice:
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October 21, 2013 at 6:35 pm
dwain.c (10/21/2013)
Illustrating what PietLinden suggested, which I like because it avoids the sort inherent in DISTINCT:
WITH SampleData AS
(
SELECT invoice_no
FROM
(
VALUES ('897456-0001')
,('897456-0002')
,('897456-0003')
,('898657-0001')
,('898657-0004')
,('889977-0003')
,('889978-0002')
,('889978-0004')
,('889979-0001')
,('889979-0010')
,('889995-0002')
,('889995-0003')
,('889995-0004')
) a (invoice_no)
)
SELECT invoice_no=MAX(invoice_no)
FROM SampleData
GROUP BY LEFT(invoice_no, 6);
I was actually going to come back and try PietLinden's suggestion as well. I always like learning multiple ways to complete a task. Thanks for your input.
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