July 20, 2009 at 8:19 pm
Hell all,
I have data three fields from one table that looks like this
subbrkIdbrksubbrk
156null
275null
336null
4null23
5null38
6null42
I need to extract the matching subbrkId from the table above and merge it to the table below, I am having issues because the brk and subbrk field values get repeated in the table below:
subbrkIdbrksubbrk
-56null
-56null
-56null
-75null
-75null
-null23
-null23
-null38
-null38
I need to update the table with the matching subbrkId as shown below:
subbrkIdbrksubbrk
156null
156null
156null
275null
275null
4null23
4null23
5null38
5null38
Any help will be MUCH appreciated! Thanks in advance
July 20, 2009 at 9:15 pm
Okay, thanks for a partial setup, but please look at how I am presenting my code, including the DDL for the tables, the insert statements with the sample data. This is how you really should provide your setup for us.
create table #TestTab1 (
subbrkId int null,
brk int null,
subbrk int null
);
insert into #TestTab1(
subbrkId,
brk,
subbrk
)
select 1, 56, null union all
select 2, 75, null union all
select 3, 36, null union all
select 4, null, 23 union all
select 5, null, 38 union all
select 6, null, 42;
-- I need to extract the matching subbrkId from the table above and merge it to the table below, I am having issues because the brk and subbrk field values get repeated in the table below:
create table #TestTab2 (
subbrkId int null,
brk int null,
subbrk int null
);
insert into #TestTab2 (
brk,
subbrk
)
select 56, null union all
select 56, null union all
select 56, null union all
select 75, null union all
select 75, null union all
select null, 23 union all
select null, 23 union all
select null, 38 union all
select null, 38;
update #TestTab2 set
subbrkId = t1.subbrkId
from
#TestTab2 t2
inner join #TestTab1 t1
on (t2.brk = t1.brk
or t2.subbrk = t1.subbrk);
select * from #TestTab2;
drop table #TestTab1;
drop table #TestTab2;
July 21, 2009 at 11:32 am
Hi Lynn,
THAT WORKED! 🙂 Thank you very much for your help
Next time, I will make sure I set up the presentation of questions the way you have suggested.
Thanks again
July 21, 2009 at 11:52 am
Thank you for the feedback.
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