August 30, 2004 at 2:44 am
Thanks Zd.
August 30, 2004 at 4:12 am
--FirstDayofMonth
select datename(dw,CONVERT(DATETIME, CONVERT(VARCHAR,datepart(M,getdate())) + '/1/' + CONVERT(VARCHAR, datepart(YYYY,getdate()))))
--LastDayOfMonth
select datename(dw,dateadd(dd,-1,dateadd(mm,1,convert(varchar(7),getdate(),120)+'-01')))
Thanks,
Ganesh
August 30, 2004 at 5:13 am
Great,
and which day is last of mont (31.1., 28.2., .......), but no datename.
thanks
August 30, 2004 at 5:20 am
To get the last day of a month one can use something like this
SELECT
DATEADD(DAY, -DAY(GETDATE()), CAST(CONVERT(CHAR(8), GETDATE(), 112) AS DATETIME))
AS Monatsultimo
However, using integer operations should be faster:
SELECT DATEADD(d,DATEDIFF(d,DAY(GETDATE()),GETDATE()),0) AS Monatsultimo
A pretty cool script comes from SQL Server MVP Steve Kass:
declare @31st datetime
set @31st = '19341031' -- any 31st
declare @now datetime
set @now = getdate()
select dateadd(month,datediff(month,@31st,@now),@31st)
Just make sure, your starting date is any valid 31st, no matter whether in the past or future.
--
Frank Kalis
Microsoft SQL Server MVP
Webmaster: http://www.insidesql.org/blogs
My blog: http://www.insidesql.org/blogs/frankkalis/[/url]
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