April 25, 2016 at 1:02 pm
Hi,
I have a requirement where I have to check for records and if Record is present for both the values, then Flag is 0 and if it is present for only one value then flag is 1.
For Example
ID Value
1 'Season16'
2 'Season16'
2 'Season15'
3 'Season15'
3 'Season15'
4 'Season16'
Now I want,
ID Flag
1 1
2 0
3 0
4 1
I.e. If ID has both Season16 and Season 15 then Flag is 0 else 1.
Can you guys pour in your thoughts?
April 25, 2016 at 1:36 pm
As simple as this, or more sophistication required?
IF OBJECT_ID('tempdb..#test', 'U') IS NOT NULL
DROP TABLE #test;
CREATE TABLE #test (Id INT, Value VARCHAR(20));
INSERT #test
(Id, Value)
VALUES (1, 'Season 16'),
(2, 'Season 16'),
(2, 'Season 15'),
(3, 'Season 15'),
(3, 'Season 15'),
(4, 'Season 16');
SELECT t.Id
, Flag = IIF(COUNT(1) > 1, 0, 1)
FROM #test t
GROUP BY t.Id;
By the way, in future, please include set-up code, as above, when posting questions like this.
The absence of evidence is not evidence of absence
- Martin Rees
The absence of consumable DDL, sample data and desired results is, however, evidence of the absence of my response
- Phil Parkin
April 27, 2016 at 11:26 pm
I notice that you're looking for multiple seasons for same ID
I.e. If ID has both Season16 and Season 15 then Flag is 0 else 1.
Since row with id = 3 has both records as "Season 15", you want the flag to be "1"
Slight modification to Phil's answer. Including "distinct" on the count would be required.
SELECT t.Id
, Flag = IIF(COUNT( distinct value) > 1, 0, 1)
FROM #test t
GROUP BY t.Id;
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