November 28, 2013 at 10:50 am
I want to extract database names from a varchar column storing connection strings.
A sample value is; 'server=SVR1;database=DB1;uid=user1;pwd=pass1;enlist=true;'
Each record might have a slightly different connection string format; Uid before Database, or no Enlist etc. 'server=SVR1;uid=user1;database=DB1;pwd=pass1;'
I have a few parsing scripts but they are not useful for this specific extraction.
Basically, I want the string starts after 'database=' and ends at the following ';'.
Thanks,
Kuzey
November 28, 2013 at 11:48 am
Found it.
SELECT
substring(substring(dbconnection,CHARINDEX('Database=',dbconnection)+9, LEN(dbconnection)),1,CHARINDEX(';',substring(dbconnection,CHARINDEX('Database=',dbconnection)+9, LEN(dbconnection)))-1)
FROM Connections
Thanks,
Kuzey
November 28, 2013 at 5:15 pm
You can expose pretty much any parameter you want regardless of position using a pattern-based string splitter like this:
WITH SampleData (ID, ConnectionString) AS
(
SELECT 1, 'server=SVR1;database=DB1;uid=user1;pwd=pass1;enlist=true'
UNION ALL SELECT 2, 'database=DB1;server=SVR1;uid=user1;pwd=pass1;enlist=true'
UNION ALL SELECT 3, 'server=SVR1;uid=user1;pwd=pass1;database=DB1;enlist=true'
),
Params AS
(
SELECT *
FROM SampleData
CROSS APPLY PatternSplitCM(ConnectionString, '[;=]')
WHERE [Matched]=0
)
SELECT ID, dbname=Item
FROM Params a
WHERE ItemNumber =
(
SELECT 2+ItemNumber
FROM Params b
WHERE a.ID = b.ID AND b.Item = 'database'
);
PatternSplitCM is a utility function that can be found in the 4th article in my signature links.
My thought question: Have you ever been told that your query runs too fast?
My advice:
INDEXing a poor-performing query is like putting sugar on cat food. Yeah, it probably tastes better but are you sure you want to eat it?
The path of least resistance can be a slippery slope. Take care that fixing your fixes of fixes doesn't snowball and end up costing you more than fixing the root cause would have in the first place.
Need to UNPIVOT? Why not CROSS APPLY VALUES instead?[/url]
Since random numbers are too important to be left to chance, let's generate some![/url]
Learn to understand recursive CTEs by example.[/url]
[url url=http://www.sqlservercentral.com/articles/St
November 28, 2013 at 6:25 pm
Great, Thanks.
Viewing 4 posts - 1 through 3 (of 3 total)
You must be logged in to reply to this topic. Login to reply