Help With a query

  • Hello,

    I am trying to retrieve distinct ClientID's that match more than 1 item for example my query is currently

    Code:
    Select distinct ClientID from ClientRegs where RegionID = 1 and RegionID = 28

    The Table structure example is

    ClientID RegionID

    222         1

    222        28

    444         1

    444        44

    So I want the above query to return only 222 because it is the only client id that has a record for RegionID 1 and 28.

    The above query doesn't work because the RegionID column will never be both 1 and 28 on the same record.

    I've also tried

    Code:
    Select distinct ClientID from ClientRegs where RegionID = 1 or RegionID = 28

    This query does not work because it will return 444 and 222.

    Does anyone know if what I'm trying to do is possible and how it would be done?

    Thanks,

    Brian

  • Here's a couple of methods:

    create table clients (clientid int, regionid int)

    insert into clients

    select 222,1

    union

    select 222,28

    union

    select 444,1

    union

    select 444,44

    select clientid from

    clients

    where regionid = 28

    and clientid in

    (

     select clientid from clients where regionid = 1

    )

    select clients.clientid

    from clients

    inner join

    (

     select clientid from clients where regionid = 1

    ) x

    on clients.clientid = x.clientid

    and regionid = 28

     

    If however, you might have any number of regionid's then you're going to need to use dynamic sql.  Let me know and I'll post you a version with dynamic sql - not very fast though.

    Dave Hilditch.

  • Here's another version that does not require any joins:

    Select ClientID from ClientRegs

    where RegionID = 1 or RegionID = 28

    group by ClientID

    having count(ClientID) > 1

    Regards

    Phil

    The absence of evidence is not evidence of absence.
    Martin Rees

    You can lead a horse to water, but a pencil must be lead.
    Stan Laurel

  • Thanks to everyone that posted. I used

    select clientid from

    clients

    where regionid = 28

    and clientid in

    (

     select clientid from clients where regionid = 1

    )

    and it works

    Enthusiast it seems your suggestion is a simple solution I may try it although I have already wrote the code using the other statement.

    Thanks For all the information.

     

     

  • I like this method! My usual solution to such requirements is to use selfjoins or EXISTS subqueries, but I think in future, at least when doing quick-n-dirty stuff in QA, I will use this method. If we switch to using IN for the (here) RegionID list, this is the quickest method (in typing terms ) to extend:

    select ID from Thing where OtherID IN ( 3,4,5 ) -- just type new ones here
    group by ID having count(ID) > 2 -- and make sure this is the number of OtherIDs to match, less one

     

  • TRY THIS:

    SELECT ClientID FROM ClientRegs WHERE RegionID=1 AND ClientID in

     (SELECT ClientID FROM ClientRegs WHERE RegionID='2')

     

    IT WORK FINE FORM ME.

  • Yeah, I usually use a self-join for something like this.  I tested it out, though, and using the group by costs half of using the self-join.

    Nice technique!  I would not have expected this result.

    create table #clients (clientid int, regionid int)

    insert into #clients

    select 222,1

    union

    select 222,28

    union

    select 444,1

    union

    select 444,44

     

    --cost = .0931

    select c1.ClientID

    From  #Clients c1

    JOIN #Clients c2 on c1.ClientID = c2.ClientID

    where c1.RegionID = 1 and c2.RegionID = 28

     

    --cost = .0490

    Select ClientID

    from #Clients

    where RegionID in( 1, 28)

    group by ClientID

    having count(ClientID) > 1

    Signature is NULL

  • If you add a clustered index to the table though....

    create clustered index idx_foo on #clients (clientid) 

    --cost = .0443

    select c1.ClientID

    From  #Clients c1

    JOIN #Clients c2 on c1.ClientID = c2.ClientID

    where c1.RegionID = 1 and c2.RegionID = 28

    --cost = .0376

    Select ClientID

    from #Clients

    where RegionID in( 1, 28)

    group by ClientID

    having count(ClientID) > 1

    Which should mean that the group by is still quicker if you trust Execution Plan cost estimation as a means of measuring the speed something will run at.  It's really just a cost for internal use - for true time estimates you should look at the statistics provided by the server.

    I ran the statistics and it looks like the group by is still quicker though.

    Dave Hilditch.

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