getting week number of the current year

  • hi guys

    i need to create a script to get week 36,37,38 and 39 of the current year.

  • Nomvula (9/17/2008)


    hi guys

    i need to create a script to get week 36,37,38 and 39 of the current year.

    No problem:

    SELECT DATEPART(YY, GETDATE()) AS CurrentYear, CAST(36 AS SMALLINT) AS [Week] UNION ALL

    SELECT DATEPART(YY, GETDATE()), 37 UNION ALL

    SELECT DATEPART(YY, GETDATE()), 38 UNION ALL

    SELECT DATEPART(YY, GETDATE()), 39

    “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw

    For fast, accurate and documented assistance in answering your questions, please read this article.
    Understanding and using APPLY, (I) and (II) Paul White
    Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

  • hi Chris

    thanks for the response, actualy i'm trying to get dates within week 36,37,38,39.

    apologies for my mistake, i didn't elaborate that thorough

  • it depends ..... What's your week 1 ??

    Microsoft starts week 1 at 1/1 :crazy:

    In my company, week 1 is the week which containns Jan 4th.

    So we always need to check and correct this when determining the week number.

    CREATE FUNCTION dbo.fn_ALZDBA_convert_date2WeekALZDBA (@RefDate datetime)

    RETURNS integer

    AS

    BEGIN

    -- 4 januari = week 1 !

    declare @ALZDBARefDayFirstWeek as datetime

    declare @ALZDBARefDayLastWeek as datetime

    declare @WrkDay as datetime

    declare @WrkWeek1 as int

    declare @WrkFirstALZDBAWeekDay1 as datetime

    declare @WrkFirstALZDBAWeekDay7 as datetime

    declare @WrkCurrentALZDBAWeekDay1 as datetime

    declare @WrkCurrentALZDBAWeekDay7 as datetime

    declare @WrkWeekYear as int

    declare @ALZDBAWeekNr as int

    declare @ALZDBAWeekOffset as int

    -- bepalen dag1 van ALZDBAweek 1 en dag1 van de @RefDate-ALZDBAWeek

    select @ALZDBARefDayFirstWeek = convert(datetime, cast(year(@RefDate) as char(4)) + '/01/04',121)

    , @ALZDBARefDayLastWeek = convert(datetime, cast(year(@RefDate) as char(4)) + '/12/31',121)

    Select @WrkWeek1 = datepart(wk,@ALZDBARefDayFirstWeek)

    , @WrkFirstALZDBAWeekDay1 = dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA(@ALZDBARefDayFirstWeek,'F')

    , @WrkFirstALZDBAWeekDay7 = dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA(@ALZDBARefDayFirstWeek,'L')

    , @WrkCurrentALZDBAWeekDay1 = dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA(@RefDate,'F')

    , @WrkCurrentALZDBAWeekDay7 = dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA(@RefDate,'L')

    -- Bij MS week1 starts at 01/01

    -- Bij ALZDBA week 1 = 04/01

    -- indien 1 jan _NIET_ in eerste ALZDBA-week valt, zit de MS één week te ver. Dus corrigeren

    Select @WrkWeekYear = datepart(yyyy,@WrkCurrentALZDBAWeekDay1)

    , @WrkDay = @WrkCurrentALZDBAWeekDay1

    IF datepart(yyyy,@WrkCurrentALZDBAWeekDay1) < datepart(yyyy,@WrkCurrentALZDBAWeekDay7)

    begin

    if @RefDate between @WrkFirstALZDBAWeekDay1 and @WrkFirstALZDBAWeekDay7

    begin

    select @ALZDBAWeekOffset = case when datepart(dd,@WrkFirstALZDBAWeekDay7) between 4 and 7

    then 0

    else 1

    end

    -- opgelet week 00 mag niet !

    select @ALZDBAWeekOffset = case datepart(wk,@WrkFirstALZDBAWeekDay1) - @ALZDBAWeekOffset

    when 0

    then 0

    else @ALZDBAWeekOffset end

    if @ALZDBAWeekOffset = 0

    begin

    Select @WrkWeekYear = datepart(yyyy,@WrkFirstALZDBAWeekDay7)

    , @WrkDay = convert(datetime, cast(datepart(yyyy,@WrkFirstALZDBAWeekDay7) as char(4)) + '/01/01',121)

    end

    else

    begin

    Select @WrkWeekYear = datepart(yyyy,@WrkFirstALZDBAWeekDay1)

    , @ALZDBAWeekOffset = 1

    end

    end

    else

    begin

    declare @WrkLastALZDBAWeekDay1 as datetime

    declare @WrkLastALZDBAWeekDay7 as datetime

    Select @WrkLastALZDBAWeekDay1 = dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA(@ALZDBARefDayLastWeek,'F')

    , @WrkLastALZDBAWeekDay7 = dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA(@ALZDBARefDayLastWeek,'L')

    if @RefDate between @WrkLastALZDBAWeekDay1 and @WrkLastALZDBAWeekDay7

    begin

    if datepart(dd,@WrkLastALZDBAWeekDay7) < 4

    begin

    select @ALZDBAWeekOffset = case when datepart(dd,@WrkFirstALZDBAWeekDay7) between 4 and 7

    then 0

    else 1

    end

    -- opgelet week 00 mag niet !

    select @ALZDBAWeekOffset = case datepart(wk,@WrkFirstALZDBAWeekDay1) - @ALZDBAWeekOffset

    when 0

    then 0

    else @ALZDBAWeekOffset end

    if @ALZDBAWeekOffset = 0

    begin

    Select @WrkWeekYear = datepart(yyyy,@WrkFirstALZDBAWeekDay7)

    end

    else

    begin

    Select @WrkWeekYear = datepart(yyyy,@WrkLastALZDBAWeekDay1)

    end

    end

    else

    begin

    select @ALZDBAWeekOffset = case when datepart(dd,@WrkLastALZDBAWeekDay7) between 4 and 7

    then 0

    else 1

    end

    -- opgelet week 00 mag niet !

    select @ALZDBAWeekOffset = case datepart(wk,@WrkLastALZDBAWeekDay1) - @ALZDBAWeekOffset

    when 0

    then 0

    else @ALZDBAWeekOffset end

    if @ALZDBAWeekOffset = 0

    begin

    Select @WrkWeekYear = datepart(yyyy,@WrkLastALZDBAWeekDay7)

    , @WrkDay = convert(datetime, cast(datepart(yyyy,@RefDate) as char(4)) + '/01/01',121)

    end

    else

    begin

    Select @WrkWeekYear = datepart(yyyy,@WrkLastALZDBAWeekDay1)

    --, @ALZDBAWeekOffset = 1

    end

    end

    end

    else

    begin

    declare @WrkFirstALZDBAWeekDay1LastYear as datetime

    declare @WrkFirstALZDBAWeekDay7LastYear as datetime

    select @ALZDBARefDayFirstWeek = convert(datetime, cast((datepart(yyyy,@RefDate) - 1) as char(4)) + '/01/04',121)

    select @WrkFirstALZDBAWeekDay1LastYear = dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA(@ALZDBARefDayFirstWeek,'F')

    , @WrkFirstALZDBAWeekDay7LastYear = dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA(@ALZDBARefDayFirstWeek,'L')

    select @ALZDBAWeekOffset = case when datepart(dd,@WrkFirstALZDBAWeekDay7LastYear) between 4 and 7

    then 0

    else 1

    end

    -- opgelet week 00 mag niet !

    select @ALZDBAWeekOffset = case datepart(wk,@WrkFirstALZDBAWeekDay1LastYear) - @ALZDBAWeekOffset

    when 0

    then 0

    else @ALZDBAWeekOffset end

    end

    end

    end

    ELSE

    begin

    select @ALZDBAWeekOffset = case when datepart(dd,@WrkFirstALZDBAWeekDay7) between 4 and 7

    then 0

    else 1

    end

    -- opgelet week 00 mag niet !

    select @ALZDBAWeekOffset = case datepart(wk,@WrkFirstALZDBAWeekDay1) - @ALZDBAWeekOffset

    when 0

    then 0

    else @ALZDBAWeekOffset end

    end

    Select @ALZDBAWeekNr = (@WrkWeekYear * 100 ) + datepart(wk,@WrkDay) - @ALZDBAWeekOffset

    RETURN (@ALZDBAWeekNr)

    END

    GO

    SET QUOTED_IDENTIFIER OFF

    GO

    SET ANSI_NULLS ON

    GO

    CREATE FUNCTION dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA (@RefDate datetime, @FirstLast char(1) = 'F')

    RETURNS datetime

    AS

    BEGIN

    -- Bij ALZDBA valt 4 januari altijd in week 1 !

    -- Bij ALZDBA is de eerste dag van de week Maandag !

    DECLARE @return_date as datetime

    declare @Firstdate datetime

    declare @WrkDate datetime

    declare @refDays int

    select @WrkDate = cast(convert(char(10), @RefDate, 121) as datetime)

    select @refDays = (datepart(dw,@WrkDate) - 1) * (-1)

    select @Firstdate = dateadd( dd, @refDays, @WrkDate)

    if @@DATEFIRST = 7 -- indien datefirst op zondag staat (default) voor ALZDBA één dagje bijtellen

    begin

    select @Firstdate = dateadd(dd, 1,@Firstdate)

    end

    if @RefDate < @Firstdate

    begin

    select @Firstdate = dateadd(dd, (-7) ,@Firstdate)

    end

    if @FirstLast = 'F'

    begin

    set @return_date = @Firstdate

    end

    else

    begin

    select @return_date = dateadd(ms,-2,dateadd(dd,7,@Firstdate))

    end

    RETURN (@return_date)

    END

    Johan

    Learn to play, play to learn !

    Dont drive faster than your guardian angel can fly ...
    but keeping both feet on the ground wont get you anywhere :w00t:

    - How to post Performance Problems
    - How to post data/code to get the best help[/url]

    - How to prevent a sore throat after hours of presenting ppt

    press F1 for solution, press shift+F1 for urgent solution 😀

    Need a bit of Powershell? How about this

    Who am I ? Sometimes this is me but most of the time this is me

  • Nomvula (9/17/2008)


    hi Chris

    thanks for the response, actualy i'm trying to get dates within week 36,37,38,39.

    apologies for my mistake, i didn't elaborate that thorough

    Which dates, Nomvula? The start and end dates of each week, all 7 days for each week, all dates or working days only? As variables or as values in a table column?

    “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw

    For fast, accurate and documented assistance in answering your questions, please read this article.
    Understanding and using APPLY, (I) and (II) Paul White
    Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

  • for instance '01/09/2008' - '07/09/2008' by looking in my calendar those dates fall in week 36 so i need to get all the dates which falls on wk 36,37,38,39

  • select dateadd(wk,36,master.dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA ('20080104', 'F'))

    , dateadd(wk,37,master.dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA ('20080104', 'F'))

    , dateadd(wk,38,master.dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA ('20080104', 'F'))

    , dateadd(wk,39,master.dbo.fn_ALZDBA_convert_date2WeekRangeALZDBA ('20080104', 'F'))

    Johan

    Learn to play, play to learn !

    Dont drive faster than your guardian angel can fly ...
    but keeping both feet on the ground wont get you anywhere :w00t:

    - How to post Performance Problems
    - How to post data/code to get the best help[/url]

    - How to prevent a sore throat after hours of presenting ppt

    press F1 for solution, press shift+F1 for urgent solution 😀

    Need a bit of Powershell? How about this

    Who am I ? Sometimes this is me but most of the time this is me

  • Nomvula (9/17/2008)


    for instance '01/09/2008' - '07/09/2008' by looking in my calendar those dates fall in week 36 so i need to get all the dates which falls on wk 36,37,38,39

    Here's a quick and dirty method using the information you have to hand - the start and end dates of week 36...

    [font="Courier New"]SELECT WeekNo+number-36 AS WeekNo,

       DATEADD(ww, number-36, StartDate) AS StartDate,

       DATEADD(ww, number-36, EndDate) AS EndDate

    FROM (SELECT 36 AS WeekNo, CAST('01/09/2008' AS DATETIME) AS StartDate, CAST('07/09/2008' AS DATETIME) AS EndDate) d,

       (SELECT CAST(36 AS INT) AS number UNION ALL SELECT 37 UNION ALL SELECT 38 UNION ALL SELECT 39) n

    --WHERE number BETWEEN 36 AND 39 -- <<< if using a "numbers" or "tally" table

    ORDER BY number[/font]

    ...which will work for this year. But you should use ALZDBA's elegant code once you've established your local rules for determining the first day of the first week of the year.

    Cheers

    ChrisM

    “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw

    For fast, accurate and documented assistance in answering your questions, please read this article.
    Understanding and using APPLY, (I) and (II) Paul White
    Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

  • hi chris i looked at that and it fine but you giving me the start and the end date but i want the list of all the dates within those week No's

  • Nomvula (9/18/2008)


    hi chris i looked at that and it fine but you giving me the start and the end date but i want the list of all the dates within those week No's

    A list or a table?

    “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw

    For fast, accurate and documented assistance in answering your questions, please read this article.
    Understanding and using APPLY, (I) and (II) Paul White
    Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

  • in my table i have a date column, the data starts from 2004 - 2008 i'm required to count all records captured from 2004 to 2008 and divide it with what has been captured in week 36,37,38 and 39.

    now what i need to do is to write a query which will retrieve all dates within the mentioned dates.

  • Is there any reason why you aren't using a start date (the first day of week 36) and an end date (the last day of week 39) for this?

    WHERE YourDateColumn >= [first day of week 36]

    AND YourDateColumn < [last day of week 39 plus 1]

    “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw

    For fast, accurate and documented assistance in answering your questions, please read this article.
    Understanding and using APPLY, (I) and (II) Paul White
    Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

  • Hi,

    this might be crude and ugle but it'll deliver what you're asking for...

    [font="Courier New"]DECLARE @STARTWEEK INT

    DECLARE @ENDWEEK INT

    SELECT @STARTWEEK = 37-- Your Start Week

    SELECT @ENDWEEK = 39 -- Your End Week

    DECLARE @JAN1 DATETIME

    DECLARE @DATE DATETIME

    DECLARE @STARTWEEKRANDOMDAY DATETIME

    DECLARE @STARTWEEKFIRSTDAY DATETIME

    DECLARE @LASTWEEKLASTDAY DATETIME

    -- Start by Getting the first date in the Year Jan1

    SELECT @JAN1 = CONVERT(DATETIME,CONVERT(VARCHAR(4),DATEPART(YEAR,GETDATE())) + '-01-01')

    -- Get A Date in your Start Week by adding weeks to Jan 1st.

    SELECT @STARTWEEKRANDOMDAY = DATEADD(WEEK,(@STARTWEEK-1),@JAN1)

    -- Get Fist Day of the Startweek ( a Sunday)

    SELECT @STARTWEEKFIRSTDAY = @STARTWEEKRANDOMDAY + 1 - DATEPART(WEEKDAY,@STARTWEEKRANDOMDAY)

    -- Get the Last Day of the End Week ( a Saturday)

    SELECT @LASTWEEKLASTDAY = DATEADD(DAY,-1,DATEADD(WEEK,(@ENDWEEK+1-@STARTWEEK),@STARTWEEKFIRSTDAY))

    SELECT @DATE = @STARTWEEKFIRSTDAY

    -- Use a table to store the date list.

    CREATE TABLE #DATES

    (

    WEEKDATE DATETIME NOT NULL

    )

    -- Loop through from StartDateFirstDay to EndDateLastDay adding to the #DATES list

    WHILE @DATE <= @LASTWEEKLASTDAY

    BEGIN

    INSERT INTO #DATES SELECT @DATE

    SELECT @DATE = DATEADD(DAY,1,@DATE)

    END

    -- Voila!

    SELECT *,DATEPART(WEEK,WEEKDATE),DATEPART(WEEKDAY,WEEKDATE),DATENAME(WEEKDAY,WEEKDATE) FROM #DATES[/font]

    Kyran

  • There is this very nice and eye-opening article concering ranges ...

    Called "The "Numbers" or "Tally" Table: What it is and how it replaces a loop."

    www.sqlservercentral.com/articles/TSQL/62867/

    Johan

    Learn to play, play to learn !

    Dont drive faster than your guardian angel can fly ...
    but keeping both feet on the ground wont get you anywhere :w00t:

    - How to post Performance Problems
    - How to post data/code to get the best help[/url]

    - How to prevent a sore throat after hours of presenting ppt

    press F1 for solution, press shift+F1 for urgent solution 😀

    Need a bit of Powershell? How about this

    Who am I ? Sometimes this is me but most of the time this is me

  • HI Try this procedure

    CREATE PROCEDURE PROC_GETWEEKNUMBERS

    @strtdate datetime,

    @enddate datetime

    AS

    DECLARE @cnt int

    DECLARE @i int

    SET @i=0

    SELECT @cnt= datediff(ww,@strtdate,@enddate)

    DECLARE @WeekNumbers Table(weeknumber int)

    DECLARE @wknum int

    SELECT @wknum=Datepart(Wk,@strtdate)

    SELECT @strtdate=Dateadd(dd,1,@strtdate)

    WHILE(@i < @CNT)

    BEGIN

    Insert into @WeekNumbers(weeknumber) values (Datepart(Wk,@strtdate))

    SELECT @strtdate=Dateadd(dd,6,@strtdate)

    SET @i=@i+1

    END

    (SELECT * from @WeekNumbers)

    GO

    After creating try this query for week numbers b/w 1st aug and 30 th aug

    EXEC dbo.PROC_GETWEEKNUMBERS '1-aug-2008','31-aug-2008'

    happy programming 😀

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