December 3, 2007 at 4:24 am
Dear All,
I want to get the records created in a particular week.
if i pass 3/12/2007 i want to get the records created in that week
December 3, 2007 at 5:34 am
Prakash (12/3/2007)
Dear All,I want to get the records created in a particular week.
if i pass 3/12/2007 i want to get the records created in that week
You could use :
datepart(wk, '3/12/2007')*53 + datepart(yyyy, '3/12/2007')
The first part gives you the week number in that year, the second part the year.
If the year is not needed (you have only data for the current year), then just use : datepart(wk, '3/12/2007')
Regards,
Andras
December 3, 2007 at 6:00 am
datepart(wk, '3/12/2007')*53 + datepart(yyyy, '3/12/2007')
The first part gives you the week number in that year, the second part the year.
Hey Andras, are u sure that will give what you said. Or you just missed something in between?
Here are the results from it...
SELECTDATEPART( wk, '3/12/2007' ) * 53 + DATEPART( yyyy, '3/12/2007' ),
DATEPART( wk, '3/12/2007' ) * 53, DATEPART( wk, '3/12/2007' ), DATEPART( yyyy, '3/12/2007' )
--Results
2590583112007
Here is what I use in my projects...
DECLARE @sdtAnyDate SMALLDATETIME
SET @sdtAnyDate = '03-Dec-2007'
SELECTDATEADD( DAY, 1 - DATEPART( dw, @sdtAnyDate), @sdtAnyDate ) AS WeekStartDate,
@sdtAnyDate AS InputDate,
DATEADD( DAY, 7 - DATEPART( dw, @sdtAnyDate ), @sdtAnyDate ) AS WeekEndDate
--Ramesh
December 3, 2007 at 6:06 am
You are right, (I probably need to sleep more) 🙂
A corrected version is:
DATEPART( wk, '3/12/2007' ) + (DATEPART( yyyy, '3/12/2007' )-1950) * 53
(the *53 should be on the year :), deducting 1950 will make the numbers even smaller)
Thanks,
Andras
December 3, 2007 at 6:14 am
Well, you need to interchange * with /
You are right, (I probably need to sleep more)
You'll surely need...:D
--Ramesh
December 3, 2007 at 6:33 am
Ramesh (12/3/2007)
Well, you need to interchange * with /
You are right, (I probably need to sleep more)
You'll surely need...:D
Actually, I did indeed mean *.
multiplying the year (or part of it) by 53 will give a unique range of 53 numbers to every year. Adding the week number withing the year to this number (sine there are no more than 53 weeks a year) will assign a unique number to any year week pair. I really should have explained this 🙂
Regards,
Andras
December 3, 2007 at 6:48 am
I still couldn't understand what you're trying to point...:unsure:
Multiplying the value gives me 3032, whereas I get 12 when divided...
I am curious to know, how the said value can be used in the context of the post?
--Ramesh
December 3, 2007 at 7:26 am
Ramesh (12/3/2007)
I still couldn't understand what you're trying to point...:unsure:Multiplying the value gives me 3032, whereas I get 12 when divided...
I am curious to know, how the said value can be used in the context of the post?
Hi Ramesh,
if one would like to group items belonging to the same week, one can assign a unique number to all days of a particular week.
For example:
12/2/20073070 (Sunday, new week, new number)
12/3/20073070
12/4/20073070
12/5/20073070
12/6/20073070
12/7/20073070
12/8/20073070
12/9/20073071 (Sunday, new week, new number)
12/10/2007 3071
12/11/20073071
12/12/20073071
12/13/20073071
12/14/20073071
12/15/20073071
12/16/20073072 (Sunday, new week, new number)
12/17/20073072
So if I want all the items that are on the week 12/2/2007, then for the dates you are checking the formula should evaluate to 3070
(which you get by evaluating it for any day in the requested week, in this case '12/3/2007').
Generating a single number is just a convenience (or not). One can find a particular week by:
DATEPART( wk, somedayfromtable ) = DATEPART( wk, '3/12/2007' ) AND (DATEPART( yyyy, somedayfromtable ) = (DATEPART( yyyy, '3/12/2007' )
The above will get the items that belong to a particular week (the week for '3/12/2007'), the single number is equivalent
to the above statement (it just maps the year and week pair to a number).
Anyway, the above approach is useful if you would like to group by rows (which is the way I mis?understood the question :blush: ). Sorry.
Your solution is also better for the original question from the point of view that it calculates the start and end date, and then it uses only datetime comparison, no need for calculations (or breaking up the datetime to a year and week number part)
Thanks for correcting me 🙂
Andras
December 3, 2007 at 7:40 am
Thanks Andras, for explaining what you meant earlier.:)
--Ramesh
December 3, 2007 at 9:07 pm
Dear All
I want the output in this way
Days No of.Requests
Mon 5
Tue 6
Wed 7
Thu 3
Fri 2
Sat 1
I will pass only the date to the query
Pls help me to solve this problem
December 3, 2007 at 10:53 pm
It would be better, if you could post your code with the results you want, rather we working blindly thinking something else:cool:
--Ramesh
December 4, 2007 at 2:06 am
Assuming more things than I care to list, a strored procedure might look like...
create procedure getThatWeek
(@inputDate datetime)
as
begin
set @inputDate = convert(varchar(10), @inputDate, 111)
select left(datename(dw,createdate),3) as ThatDay ,NumOfRequests
from YourRequestLogTable
where createdate >= dateadd(dd, 1 - datepart(dw, @inputDate), @inputDate)
and createdate < dateadd(dd, 8 - datepart(dw, @inputDate), @inputDate)
end
December 4, 2007 at 2:18 am
Prakash (12/3/2007)
Dear AllI want the output in this way
Days No of.Requests
Mon 5
Tue 6
Wed 7
Thu 3
Fri 2
Sat 1
I will pass only the date to the query
Pls help me to solve this problem
Hmm, having misunderstood your original question (and suspecting that I'm not alone), and being curious enough about the problem, I'm wondering if you could explain it in more detail. Jeff Moden has a brilliant guideline about how to describe your question so that you can get a result you are happy with quickly 🙂 You can access this on http://www.sqlservercentral.com/articles/Best+Practices/61537/
Regards,
Andras
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