get value of variable

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get value of variable

dallas13

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Points: 7491
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December 28, 2009 at 2:47 pm

#137761

hi, plz execute above code in Query analyzer.
declare @year char(4)
Declare @visa varchar(25)
declare @visa1985 varchar(25)
set @visa ='56'
Set @year ='1985'
select @visa = '@visa' + ''+@year+''
Print @visa
Exec('select '''+@visa+'''')
It will display @visa1985 as output but instead i want the value of @visa1985
to be printed. Can any one help me how to do that? Thanks

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Ron McCullough SSC Guru Points: 63877 More actions · Answer 1

Is this what you are looking for?

select @visa = @visa + @year --note removed '

Print @visa

SET @visa1985 = 'select '''+@visa+''''

PRINT @Visa1985

Returns:

561985

select '561985'

If everything seems to be going well, you have obviously overlooked something.

Ron

Please help us, help you -before posting a question please read[/url]
Before posting a performance problem please read[/url]

dallas13 SSCertifiable Points: 7491 More actions · Answer 2

ummm not really. i have years starting from 1985 to 2009 and it will increase every year so next year 2010 will be added.

@visa1985 is a parameter like wise we have parameters upto @visa2009. And all these parameters have different values that user will pass from SP.

I am trying to minimize my code here thats why i m dynamically selecting @visa1985, @visa1986 from my while loop but i want actual value of @visa1985 to be displayed.

I hope u got what i want to tell. Thanks

Ron McCullough SSC Guru Points: 63877 More actions · Answer 3

dallas13

Sorry, but I am rather dense, and do not understand your amplified explanation. Some items is question:

1. Does user pass in a single parameter value?

2. If more than one parameter value, must values for each declared parameter be supplied?

3. You have posted this question to a SQL 2005 forum and yet want to run the code in Query Analyzer which is a SQL 2000 interface. Which is it 2000 ot 2005?

How about posting your T-SQL code in its entirety and maybe some one can and will assist you further.

If everything seems to be going well, you have obviously overlooked something.

Ron

Please help us, help you -before posting a question please read[/url]
Before posting a performance problem please read[/url]

Jeff Moden SSC Guru Points: 1004356 More actions · Answer 4

declare @year char(4)

Declare @visa varchar(25)

declare @visa1985 varchar(25)

set @visa ='56'

Set @year ='1985'

--select @visa = '@visa' + ''+@year+''

--Print @visa

--

--Exec('select '''+@visa+'''')

SELECT @visa = @visa+@Year

SELECT @visa

--Jeff Moden

RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

Change is inevitable... Change for the better is not.

Helpful Links:
How to post code problems
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Create a Tally Function (fnTally)

dallas13 SSCertifiable Points: 7491 More actions · Answer 5

Sorry, but I am rather dense, and do not understand your amplified explanation. Some items is question:

1. Does user pass in a single parameter value?

--no users can pass any number of parameters. They can pass @visa1985 =int, @visa1990 =null,

@visa1995 =int.means they can pass values and if they don’t want to then its null

2. If more than one parameter value, must values for each declared parameter be supplied?

3. You have posted this question to a SQL 2005 forum and yet want to run the code in Query Analyzer which is a SQL 2000 interface. Which is it 2000 ot 2005?

--its sql 2005 question.

I am still not able to get what I want from above code. I want @visa1985 = 56 or any int value that can be supplied and I don’t want @visa1985 = 561985. I hope I m able to explain it properly.

S3ssion SSChasing Mays Points: 602 More actions · Answer 6

declare @year char(4)

Declare @visa varchar(25)

declare @visa1985 varchar(25)

Set @year ='1985'

set @visa ='56'

set @visa = '@visa' + ''+@year+'' +'=' + @visa

select @visa

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