October 18, 2016 at 7:32 am
Hi ,
I need to write a query for teachers who dont have classes on a particular day.
like ex: name, day, courseid
Mary, MON, Science
Surya, TUE ,Maths
Mary, TUE ,Biology
The teacher teach a particular course on the particular day. Ex: Mary is not teaching on Wed, Thur, Fri.
I need to get the data to find when the teacher is free(Wed, Thur, Fri) so the students can meet him/her for a free session/doubts.
Please help.
October 18, 2016 at 7:57 am
sindhupavani123 (10/18/2016)
Hi ,I need to write a query for teachers who dont have classes on a particular day.
like ex: name, day, courseid
Mary, MON, Science
Surya, TUE ,Maths
Mary, TUE ,Biology
The teacher teach a particular course on the particular day. Ex: Mary is not teaching on Wed, Thur, Fri.
I need to get the data to find when the teacher is free(Wed, Thur, Fri) so the students can meet him/her for a free session/doubts.
Please help.
Can you provide some sample DDL, INSERT statements and desired results, as described in the link in my signature, please. Do this, and you should get a working solution in return.
The absence of evidence is not evidence of absence
- Martin Rees
The absence of consumable DDL, sample data and desired results is, however, evidence of the absence of my response
- Phil Parkin
October 18, 2016 at 8:00 am
Pretty sparse on details here. I notice you are very new around here so I decided to help you out with some ddl and sample data so you can see how you should do this in the future.
I think you are looking for something like this.
create table #something
(
name varchar(10)
, day char(3)
, courseid varchar(10)
)
insert #something
select 'Mary', 'MON', 'Science' union all
select 'Surya', 'TUE', 'Maths' union all
select 'Mary', 'TUE', 'Biology'
create table #Days
(
NameOfDay char(3)
)
insert #Days (NameOfDay)
values ('MON'),('TUE'),('WED'),('THU'),('FRI')
select *
from #Days d
left join #something s on s.day = d.NameOfDay
and s.name = 'Mary'
where s.day is null
_______________________________________________________________
Need help? Help us help you.
Read the article at http://www.sqlservercentral.com/articles/Best+Practices/61537/ for best practices on asking questions.
Need to split a string? Try Jeff Modens splitter http://www.sqlservercentral.com/articles/Tally+Table/72993/.
Cross Tabs and Pivots, Part 1 – Converting Rows to Columns - http://www.sqlservercentral.com/articles/T-SQL/63681/
Cross Tabs and Pivots, Part 2 - Dynamic Cross Tabs - http://www.sqlservercentral.com/articles/Crosstab/65048/
Understanding and Using APPLY (Part 1) - http://www.sqlservercentral.com/articles/APPLY/69953/
Understanding and Using APPLY (Part 2) - http://www.sqlservercentral.com/articles/APPLY/69954/
October 18, 2016 at 8:15 am
Thank you.
Its quite close to what i expect
In your query 'left join #something s on s.day = d.NameOfDay
and s.name = 'Mary'' you are trying to retrieve data for only one teacher .
But my requirement is to get all the teachers with their nameas well as respective free days:
like,
name, day, courseid
mary , wed ,NULL
THU ,NULL
fri , NULL
Surya Mon Null
WEd Null
Thu Null
October 18, 2016 at 8:28 am
sindhupavani123 (10/18/2016)
Thank you.Its quite close to what i expect
In your query 'left join #something s on s.day = d.NameOfDay
and s.name = 'Mary'' you are trying to retrieve data for only one teacher .
But my requirement is to get all the teachers with their nameas well as respective free days:
like,
name, day, courseid
mary , wed ,NULL
THU ,NULL
fri , NULL
Surya Mon Null
WEd Null
Thu Null
If what I attempted is not what you are after then you need to provide more details about what you expect. I gave you a pretty good example of how to post sample data. Can you hard code a select statement that would be representative of what you want for output from your sample data?
_______________________________________________________________
Need help? Help us help you.
Read the article at http://www.sqlservercentral.com/articles/Best+Practices/61537/ for best practices on asking questions.
Need to split a string? Try Jeff Modens splitter http://www.sqlservercentral.com/articles/Tally+Table/72993/.
Cross Tabs and Pivots, Part 1 – Converting Rows to Columns - http://www.sqlservercentral.com/articles/T-SQL/63681/
Cross Tabs and Pivots, Part 2 - Dynamic Cross Tabs - http://www.sqlservercentral.com/articles/Crosstab/65048/
Understanding and Using APPLY (Part 1) - http://www.sqlservercentral.com/articles/APPLY/69953/
Understanding and Using APPLY (Part 2) - http://www.sqlservercentral.com/articles/APPLY/69954/
October 18, 2016 at 8:36 am
Still kind of guessing here. I assume you have a table with the teachers in it that you could use for this. Since it is unclear I created a cte to simulate this table.
create table #something
(
name varchar(10)
, day char(3)
, courseid varchar(10)
)
insert #something
select 'Mary', 'MON', 'Science' union all
select 'Surya', 'TUE', 'Maths' union all
select 'Mary', 'TUE', 'Biology'
create table #Days
(
NameOfDay char(3)
)
insert #Days (NameOfDay)
values ('MON'),('TUE'),('WED'),('THU'),('FRI');
with Teachers as --hopefully you have a table with names, I am deriving one here
(
select Name
from #something
group by name
)
select *
from #Days d
cross join Teachers t
left join #something s on s.name = t.name and s.day = d.NameOfDay
where s.name is null
drop table #something
drop table #Days
_______________________________________________________________
Need help? Help us help you.
Read the article at http://www.sqlservercentral.com/articles/Best+Practices/61537/ for best practices on asking questions.
Need to split a string? Try Jeff Modens splitter http://www.sqlservercentral.com/articles/Tally+Table/72993/.
Cross Tabs and Pivots, Part 1 – Converting Rows to Columns - http://www.sqlservercentral.com/articles/T-SQL/63681/
Cross Tabs and Pivots, Part 2 - Dynamic Cross Tabs - http://www.sqlservercentral.com/articles/Crosstab/65048/
Understanding and Using APPLY (Part 1) - http://www.sqlservercentral.com/articles/APPLY/69953/
Understanding and Using APPLY (Part 2) - http://www.sqlservercentral.com/articles/APPLY/69954/
October 18, 2016 at 9:43 am
this is what i need..thanks so much..
Viewing 7 posts - 1 through 6 (of 6 total)
You must be logged in to reply to this topic. Login to reply