function with alphabet

Question

function with alphabet

Helical Johan

Ten Centuries

Points: 1033
More actions
August 4, 2008 at 8:46 am

#195182

I have a string, for example,
'CHARLES H#L6CAL JOEL4',
but i need to validate this string. It only may have alphabet letter.
any ideas?
thanks.

Viewing 7 posts - 1 through 6 (of 6 total)

You must be logged in to reply to this topic. Login to reply

ChrisM@Work SSC Guru Points: 186127 More actions · Answer 1

How about a little more information? What do you want to do if the string contains something other than a letter? Such as

report an error

not import the row into a table

replace non-letters with something?

Cheers

ChrisM

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

Helical Johan Ten Centuries Points: 1033 More actions · Answer 2

Hi, this string only may have alphabet letter, otherwise report an error.

Thanks

ChrisM@Work SSC Guru Points: 186127 More actions · Answer 3

declare @Return varchar(30), @String varchar(30)

set @Return = ''

set @String = 'CHARLES H#L6CAL JOEL4'

SELECT @Return = @Return + SUBSTRING(@String,number,1)

FROM dbo.Numbers WITH (NOLOCK)

WHERE number <= LEN(@String)

AND UPPER(SUBSTRING(@String,number,1)) LIKE '%[^A-Z]%'

SELECT CASE WHEN LEN(@Return) = 0 THEN 'String Ok' else 'Error' End

set @Return = ''

set @String = 'CHARLESHLCALJOEL'

SELECT @Return = @Return + SUBSTRING(@String,number,1)

FROM dbo.Numbers WITH (NOLOCK)

WHERE number <= LEN(@String)

AND UPPER(SUBSTRING(@String,number,1)) LIKE '%[^A-Z]%'

SELECT CASE WHEN LEN(@Return) = 0 THEN 'String Ok' else 'Error' End

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

Helical Johan Ten Centuries Points: 1033 More actions · Answer 4

Helical Johan

Ten Centuries

Points: 1033

August 4, 2008 at 9:32 am

#852749

OK.THANKS .....

ChrisM@Work SSC Guru Points: 186127 More actions · Answer 5

You're welcome :unsure::ermm:

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

antonio.collins SSCrazy Eights Points: 9600 More actions · Answer 6

no need for a numbers table.

declare @t table ( string varchar(255))

insert into @t

select 'CHARLES H#L6CAL JOEL4'

union select 'CHARLESHLCALJOEL'

union select 'red and green'

union select 'RedAndGreen'

union select 'RedAndGreen.'

select string, case when string like '%[^A-Z]%' then 0 else 1 end as zero_if_invalid

from @t