September 15, 2010 at 9:41 pm
Comments posted to this topic are about the item Fun with Transactions - Part II
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Nakul Vachhrajani.
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September 15, 2010 at 10:01 pm
Another good question, thanks!
September 15, 2010 at 10:33 pm
Good question. I think it is worth noting that this behavior is exhibited because nested transactions do not truly exist in SQL Server.
Jason...AKA CirqueDeSQLeil
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September 16, 2010 at 1:30 am
CirquedeSQLeil (9/15/2010)
Good question. I think it is worth noting that this behavior is exhibited because nested transactions do not truly exist in SQL Server.
I have to disagree with you, Jason. Nested transactions do exist, and they work exactly as I think common sense dictates.
Transactions are primarily intended to implement the A and I of the ACID properties: atomicity and isolation. Nessting fringes with that goal, and I can easily imagine that the people on the ANSI committee have considered not allowing nested transactions. But that would invalidate many common use cases. If I write a stored procedure that does multiple things but should be considered as a single unit of work, I use BEGIN TRAN and COMMIT TRAN (or ROLLBACK TRAN in case of error) in the procedure code. But what if I next have to implement a stored procedure that is also considered a single unit of work, but that includes the first stored procedure? I use BEGIN TRAN/COMMIT TRAN in the outer procedure; I call the inner procedure, and there we have the nesting. Prohibiting nesting would requiere me to duplicate the code, which I obviously don't want.
Support for nested transactions is unavoidable. But what are the "most correct" semantics? Consider the example above. The inner stored procedure implements actions 2.1 and 2.2, as a single unit of work. The outer stored procedure implements actions 1, 2.1, 2,2, and 3, also as a single unit of work. And it does so by caling the inner procedure.
So what should a nested COMMIT do? It can not really commit the changes of actions 2.1 and 2.2. After all, action 3 might still fail, and in that case the whole outer procedure needs to be rolled back, including actions 2.1 and 2.2. Otherwise, the outer procedure would not be atomic. So the only thing the COMMIT can do is to decrease the nesting level counter; actually committing the data has to be postponed until all nesteed transactions have finished.
Conversely, a ROLLBACK in the nested transaction should roll back ALL open transactions. If it would only rollback the effects of the nested transaction, the outer procedure could continue to perform action 3 and commit. IN that case, actions 1 and 3 are committed, but actions 2.1 and 2.2 are not. The procedure is no longer ACID. Making any rollback, regardless of nesting level, roll back ALL open work prevents that problem.
This question is actually almost similar to the one two days ago. The only real difference is the use of the extra keywork WORK (that is not required).
September 16, 2010 at 1:35 am
CirquedeSQLeil (9/15/2010)
Good question. I think it is worth noting that this behavior is exhibited because nested transactions do not truly exist in SQL Server.
It is worth mentioning that although nested transaction doesn't exist in SQL Server, you can still rollback parts of transaction and commit the rest of the transaction with the use of save points
Adi
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September 16, 2010 at 1:35 am
Hugo Kornelis (9/16/2010)
This question is actually almost similar to the one two days ago. The only real difference is the use of the extra keywork WORK (that is not required).
That is correct, Hugo. In fact there are 2 more on similar lines coming up. I originally encountered the behaviour that was covered in the question 2 days ago. The rest of the questions are derivatives of my research on the original question.
I hope you like them all 🙂
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Nakul Vachhrajani.
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September 16, 2010 at 2:04 am
Great question!
I didn't know about the ROLLBACK WORK syntax, so I definitely learned something today.
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September 16, 2010 at 4:28 am
i strongly disagree with you.. as the rollback/commit statments does not work for alias unless preceeded by TRAN or TRANSACTION so the syntax error.... i chose answer "Error : incorrect syntax".. this is not articulated proper and I lost 2 points here....:(
September 16, 2010 at 4:44 am
vinod.andani-874416 (9/16/2010)
i strongly disagree with you.. as the rollback/commit statments does not work for alias unless preceeded by TRAN or TRANSACTION so the syntax error.... i chose answer "Error : incorrect syntax".. this is not articulated proper and I lost 2 points here....:(
Well, it does work:
http://msdn.microsoft.com/en-us/library/ms174973.aspx
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September 16, 2010 at 5:03 am
vinod.andani-874416 (9/16/2010)
i strongly disagree with you.. as the rollback/commit statments does not work for alias unless preceeded by TRAN or TRANSACTION so the syntax error.... i chose answer "Error : incorrect syntax".. this is not articulated proper and I lost 2 points here....:(
Vinod,
The "WORK" is not an alias - it's sort-of a keyword. It's not even required - Issuing a simple ROLLBACK (without a user-defined transaction name) is same as issuing a ROLLBACK WORK. You can refer to Hugo's explanation as to how nested transactions work and why ROLLBACK WORK rolls back to the outermost transaction.
From the MSDN Link referenced, "This statement functions identically to ROLLBACK TRANSACTION except that ROLLBACK TRANSACTION accepts a user-defined transaction name."
Sorry that you lost 2 points (there are lots more on SSC to win), but I hope that you learnt the use of "ROLLBACK WORK" and how transactions behave.
Thanks & Regards,
Nakul Vachhrajani.
http://nakulvachhrajani.com
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September 16, 2010 at 5:12 am
Nice question and good explanation from Hugo. Thanks 🙂
Thanks
September 16, 2010 at 6:40 am
Nakul Vachhrajani (9/16/2010)
Hugo Kornelis (9/16/2010)
This question is actually almost similar to the one two days ago. The only real difference is the use of the extra keywork WORK (that is not required).That is correct, Hugo. In fact there are 2 more on similar lines coming up. I originally encountered the behaviour that was covered in the question 2 days ago. The rest of the questions are derivatives of my research on the original question.
I hope you like them all 🙂
Ah crap. Not more. Have already lost 4 points aint that enough... have mercy 😉
September 16, 2010 at 6:55 am
Great question, great follow on discussion. Thanks.
September 16, 2010 at 7:57 am
Thanks Hugo for the explanation.
September 16, 2010 at 8:05 am
Thanks Nakul for a very good question and to Hugo for the detailed explanation.
Steve Jimmo
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