October 23, 2024 at 4:32 pm
Hi there,
I've tried CROSS APPLY, PATINDEX and many other functions, but can't nail this.
For each record, I want to extract all numbers which follow a '#' and then create a new row for each.
Example String 1: "Hello world. #1234 has been replaced by #014521"
To return:
1234
014521
Example String 2: "#687459"
To return:
687459
If there is no number, then leave blank.
Thanks in advance. 🙂
October 23, 2024 at 5:09 pm
One possibility
DECLARE @x VARCHAR(500) = 'Hello world. #1234 has been replaced by #014521';
SELECT STUFF (value, 1, 1, '')
FROM STRING_SPLIT(@x, ' ')
WHERE LEFT(value, 1) = '#';
The absence of evidence is not evidence of absence.
Martin Rees
You can lead a horse to water, but a pencil must be lead.
Stan Laurel
October 23, 2024 at 6:03 pm
An alternative (maybe slightly less overhead?, esp. for long strings):
SELECT LEFT(item, CHARINDEX(' ', item + ' ')) AS value
FROM dbo.DelimitedSplit8K (@x, '#') /*or STRING_SPLIT(), if available to you AND
the order of values doesn't have to be the same as the original data*/WHERE LEFT(item, 1) LIKE '[0-9]';
SQL DBA,SQL Server MVP(07, 08, 09) "It's a dog-eat-dog world, and I'm wearing Milk-Bone underwear." "Norm", on "Cheers". Also from "Cheers", from "Carla": "You need to know 3 things about Tortelli men: Tortelli men draw women like flies; Tortelli men treat women like flies; Tortelli men's brains are in their flies".
October 23, 2024 at 9:12 pm
... extract all numbers which follow a '#' and then create a new row for each.
So far I'm not seeing a solution for which each character returned is an integer. Try this counterexample
DECLARE @x VARCHAR(500) = '#X12R #12X D34';
SELECT LEFT(item, CHARINDEX(' ', item + ' ')) AS value
FROM dbo.DelimitedSplit8K_Lead (@x, '#') /*or STRING_SPLIT(), if available to you AND
the order of values doesn't have to be the same as the original data*/WHERE LEFT(item, 1) LIKE '[0-9]';
SELECT STUFF (value, 1, 1, '')
FROM STRING_SPLIT(@x, ' ')
WHERE LEFT(value, 1) = '#';
Maybe something like this
select *
from (values ('#1234 has #1 been replaced by #014521'),
(' #1234 has 555 been replaced by #014521'),
('#X12R #12X D34'),
('Hello world. #X1234 has been replaced by #014#s521'),
(' #123456')) v(test_string)
cross apply string_split(v.test_string, '#', 1) ss
cross apply (values (patindex('%[^0-9]%', ss.[value]))) ndx(non_integer)
cross apply (values (iif(ndx.non_integer>0, left(ss.[value], ndx.non_integer-1), ss.[value]))) results(val)
where len(results.val)>0
order by v.test_string, ss.ordinal;
First, the code splits the input string on # using STRING_SPLIT and specifying the optional 3rd parameter so that an ordinal output column is generated. Next, PATINDEX is used to search the split values for the first non 0-9 integer by offset position. Last, if the non integer position is greater than 0 then substring to get the numerical characters using LEFT, otherwise return the whole split value
Aus dem Paradies, das Cantor uns geschaffen, soll uns niemand vertreiben können
October 23, 2024 at 10:11 pm
Good point. I was in too much of a hurry when I wrote the other code:
DECLARE @x varchar(500) = 'xxx. #1234 has been replaced by #014521 #1a23 #23 #4c';
SELECT *
FROM dbo.DelimitedSplit8K (@x, '#')
CROSS APPLY (
SELECT LEFT(item, CHARINDEX(' ', item + ' ') - 1) AS value
) AS ca1
WHERE value NOT LIKE '%[^0-9]%'
:
SQL DBA,SQL Server MVP(07, 08, 09) "It's a dog-eat-dog world, and I'm wearing Milk-Bone underwear." "Norm", on "Cheers". Also from "Cheers", from "Carla": "You need to know 3 things about Tortelli men: Tortelli men draw women like flies; Tortelli men treat women like flies; Tortelli men's brains are in their flies".
October 24, 2024 at 10:03 am
Thank you Phil, Scott and Steve for your informative and concise replies! Much appreciated.
I'm struggling with one thing: dbo.DelimitedSplit8K. What is this?
Many thanks! 🙂
Footnote... Steve: I'm getting this error for the following SQL, "Procedure or function string_split has too many arguments specified"
select *
from (values ('#1234 has #1 been replaced by #014521'),
(' #1234 has 555 been replaced by #014521'),
('#X12R #12X D34'),
('Hello world. #X1234 has been replaced by #014#s521'),
(' #123456')) v(test_string)
cross apply string_split(v.test_string, '#', 1) ss
cross apply (values (patindex('%[^0-9]%', ss.[value]))) ndx(non_integer)
cross apply (values (iif(ndx.non_integer>0, left(ss.[value], ndx.non_integer-1), ss.[value]))) results(val)
where len(results.val)>0
order by v.test_string, ss.ordinal;
October 24, 2024 at 10:17 am
Check this article for the DelimitedSplit8k function:
We have assumed that you are using SQL Server 2022, as that is the forum you have posted in. The third argument of string_split() was introduced in 2022, so if you are using an earlier version (or your database has an earlier compatibility level) you will get the error you are seeing.
The absence of evidence is not evidence of absence.
Martin Rees
You can lead a horse to water, but a pencil must be lead.
Stan Laurel
October 24, 2024 at 10:29 am
I have SQL Server Management Studio v19.0.1 and 18.12.1 installed. Are these compatible?
October 24, 2024 at 10:34 am
That was not an SSMS error, it was an error generated by the server when attempting to execute your query. You can see your SQL Server version by running this:
SELECT
Version = SERVERPROPERTY('productversion')
, Level = SERVERPROPERTY('productlevel')
, Edition = SERVERPROPERTY('edition');
The absence of evidence is not evidence of absence.
Martin Rees
You can lead a horse to water, but a pencil must be lead.
Stan Laurel
October 24, 2024 at 10:38 am
I see. This is what it's giving me:-
Version Level Edition
15.0.4261.1 RTM Enterprise Edition (64-bit)
Version Level Edition
15.0.4395.2 RTM Enterprise Edition (64-bit)
Many thanks Phil.
October 24, 2024 at 10:42 am
That is SQL Server 2019, which explains the error message.
If you need to guarantee that your results are presented in the order in which they appeared in the original string, using DelimitedSplit8k is the way I would recommend.
The absence of evidence is not evidence of absence.
Martin Rees
You can lead a horse to water, but a pencil must be lead.
Stan Laurel
October 24, 2024 at 10:47 am
Thank you for clarifying Phil. 🙂
October 24, 2024 at 11:03 am
Thank you all for your detailed feedback. I shall use this when we eventually get 2022!
Have posted this in 2019 forum.
Many thanks.
October 24, 2024 at 1:45 pm
I'm struggling with one thing: dbo.DelimitedSplit8K. What is this?
You can get the code for it in the "Resources" section at the following article, which explains how it works, as well. It does what Microsoft finally made the STRING_SPLIT() function do 6 years after if first came out.
--Jeff Moden
Change is inevitable... Change for the better is not.
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