Find last business day from table with date and day in SQL 2008 and 2012

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Find last business day from table with date and day in SQL 2008 and 2012

prafullaahirrao

Old Hand

Points: 308
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November 29, 2016 at 4:15 am

#401130

Hi All,
I need last business day from a table with ID,date and day column in it.
For e.g.
IDDate Day
11-Jan-2016 Friday
22-Jan-2016 Saturday
33-Jan-2016 Sunday
.
.
29 29-Jan-2016 Friday
30 30-Jan-2016 Saturday
31 31-Jan-2016 Sunday
32 1-Feb-2016 Monday
33 2-Feb-2016 Tuesday
.
.
60 29-Feb-2016 Monday
and so on....
so I need
29-Jan-2016 Friday(Excluding Saturday and Sunday)
29-Feb-2016 Monday
.
.
.
Thanks

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Lowell SSC Guru Points: 323518 More actions · Answer 1

A Calendar Table is really handy for this.

As an Inline calculation

the way i would tackle it is with DateMath, and a case statement that checks for Saturday or Sunday

here i created 64 months if dates, and used a calculation to confirm i was getting the last biz day of the month:

does this look right?

/*

TheDate LastDayOfMonth DatePartOfLastDay DateNameOfLastDay LastBizDay LastBizDayOfWeek

2016-01-15 00:00:00.000 2016-01-31 1 Sunday 2016-01-29 Friday

2016-02-15 00:00:00.000 2016-02-29 2 Monday 2016-02-29 Monday

2016-03-15 00:00:00.000 2016-03-31 5 Thursday 2016-03-31 Thursday

*/

WITH ExampleMonths

AS

(

SELECT DATEADD(mm,MiniTally.N,'2015-01-15') AS TheDate

FROM (select row_number() over (order by num) -1 as N

from (values (1)) t (num)

group by cube (num, num, num, num, num, num) --2^6 = 64 ,more num = another order power of 2)

) MiniTally

)

select TheDate,

DATEADD(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0)) AS ABitLessThanFirstOfMonth,

CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0))) AS LastDayOfMonth,

DATEPART(weekday,(CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0))))) AS DatePartOfLastDay,

DATENAME(dw,(CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0))))) AS DateNameOfLastDay,

CASE

WHEN DATEPART(weekday,(CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0))))) IN (7) --Saturday

THEN DATEADD(dd,-1,

CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0)))

)

WHEN DATEPART(weekday,(CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0))))) IN(1) --Sunday

THEN DATEADD(dd,-2,

CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0)))

)

ELSE CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0)))

END AS LastBizDay,

DATENAME(dw,CASE

WHEN DATEPART(weekday,(CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0))))) IN (7) --Saturday

THEN DATEADD(dd,-1,

CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0)))

)

WHEN DATEPART(weekday,(CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0))))) IN(1) --Sunday

THEN DATEADD(dd,-2,

CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0)))

)

ELSE CONVERT(DATE,dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,TheDate ) + 1, 0)))

END) AS LastBizDayOfWeek

FROM ExampleMonths

Lowell

--help us help you! If you post a question, make sure you include a CREATE TABLE... statement and INSERT INTO... statement into that table to give the volunteers here representative data. with your description of the problem, we can provide a tested, verifiable solution to your question! asking the question the right way gets you a tested answer the fastest way possible!

John Mitchell-245523 SSC Guru Points: 148809 More actions · Answer 2

Isn't it as simple as this?

SELECT DISTINCT

MAX(TheDate) OVER(PARTITION BY YEAR(MyDate), MONTH(MyDate)) AS LastBizofMonth

,MyDay

FROM MyTable

WHERE MyDay NOT IN ('Saturday', 'Sunday')

By the way, please don't double-post.

John

Thom A SSC Guru Points: 99133 More actions · Answer 3

John Mitchell-245523 (11/29/2016)
Isn't it as simple as this?
SELECT DISTINCT
MAX(TheDate) OVER(PARTITION BY YEAR(MyDate), MONTH(MyDate)) AS LastBizofMonth
,MyDay
FROM MyTable
WHERE MyDay NOT IN ('Saturday', 'Sunday')
By the way, please don't double-post.
John

Depends on the OP's definition of a Working Day. For example, I need to omit Public Holiday's as well as weekends. This also includes Observed holidays, such as Christmas Day this year, due to it falling on a Sunday (it is therefore observed on the Tuesday, as that is the next non public holiday weekday).

Thom~

Excuse my typos and sometimes awful grammar. My fingers work faster than my brain does.
Larnu.uk

prafullaahirrao Old Hand Points: 308 More actions · Answer 4

prafullaahirrao

Old Hand

Points: 308

November 29, 2016 at 8:20 am

#1914968

Thanks John

Alan Burstein SSC Guru Points: 61141 More actions · Answer 5

Using this sample data:

CREATE TABLE #myTable (dt date UNIQUE NOT NULL);

WITH E AS (SELECT v FROM (VALUES (1),(1),(1),(1),(1),(1)) t(v))

INSERT #myTable

SELECT CAST(DATEADD(DAY, ROW_NUMBER() OVER (ORDER BY (SELECT 1))-1, '20140101') AS date)

FROM E a, E b, E c, E d;

You could do this:

SELECT [date] = MAX(dt),

[day] = DATENAME(WEEKDAY,MAX(dt))

FROM #myTable

WHERE DATENAME(WEEKDAY,dt) NOT IN ('Saturday', 'Sunday')

GROUP BY DATEPART(YEAR,dt), DATEPART(MONTH,dt)

ORDER BY MAX(dt); -- not required, including for readability

"I cant stress enough the importance of switching from a sequential files mindset to set-based thinking. After you make the switch, you can spend your time tuning and optimizing your queries instead of maintaining lengthy, poor-performing code."

-- Itzik Ben-Gan 2001