July 18, 2008 at 3:38 am
how to find 2nd highest value in a table 🙂
July 18, 2008 at 4:21 am
select top 1 * from (select top n * from dbo.emp order by sal desc) a order by sal
😀
July 18, 2008 at 4:24 am
You can change and use it for getting nth highest salary from Employee table as follows
SELECT TOP 1 salary
FROM (
SELECT DISTINCT TOP n salary
FROM employee
ORDER BY salary DESC) a
ORDER BY salary
where n > 1 (n is always greater than one)
😉
July 18, 2008 at 4:50 am
Create table tmp_table (name varchar(20),age int)
Insert into tmp_table Values('Hari',27)
Insert into tmp_table Values('Sai gopal',27)
Insert into tmp_table Values('Jeeva',29)
Insert into tmp_table Values('Shanmuga Raja',25)
Insert into tmp_table Values('Senthil',26)
Insert into tmp_table Values('Sandesh',27)
Insert into tmp_table Values('Segu',25)
)
Select * From tmp_table
select * from tmp_table m1
where (0)=(select count(distinct(m2.age))
from tmp_table m2 where
m2.age>m1.age)
--Drop table tmp_table
July 18, 2008 at 5:01 am
Try this
SELECT TOP 1 YourField
FROM
(SELECT TOP 2 YourField
FROM TABLE
ORDER BY YourField DESC) AS DATA
ORDER BY YourField
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