Use SUBSTRING in conjunction with a CHARINDEX function. CHARINDEX will allow you to find the starting point of your return string
Something like:
declare @fun varchar(75)
set @fun='ZION , IL 60099'
select substring(@fun,charindex(',',@fun)+1,len(@fun))
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Your lack of planning does not constitute an emergency on my part...unless you're my manager...or a director and above...or a really loud-spoken end-user..All right - what was my emergency again?