December 29, 2004 at 7:00 am
FindWhat.com (NASDAQ: FWHT) creates and offers proprietary performance-based marketing and commerce enabling services that help businesses of all sizes throughout the business cycle in reaching prospects, converting prospects to customers and then retaining those customers. Its marketing division creates online marketplaces where buyers are introduced to sellers at exactly the right moment, when they are searching for products and services on the Internet; this introduction is based on a bid-for-position, pay-per-click and pay-per-call (U.S. only), keyword-targeted advertising service. FindWhat.com offers this service directly to advertisers through the FindWhat.com Network™ in the
We are seeking an Internet Software Developer to join our Technology Team.
Qualified candidates will possess creativity, excellent verbal and written communication skills and strong organizational, analytical and problem solving skills. Must be highly motivated, deadline oriented and able to work within cross-functional teams. Project management experience required.
Candidate will be responsible for design, development and testing of software application that is vital to FindWhat.com. Candidate will also be responsible for writing documentation necessary to support development.
• 5+ years of enterprise software development experience
• Bachelors Degree in Computer Science or a closely-related field (MS or Ph.D. a plus).
• SQL Server programming, .Net ASP, Visual Basic, Internet programming concepts with an emphasis on Microsoft Tools.
• Substantial knowledge of Windows environments.
• Extensive experience designing and programming enterprise, distributed systems, and/or developing large software systems.
• Fluency in English.
January 3, 2005 at 8:00 am
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January 3, 2005 at 8:19 am
Jason,
I am not familiar with Ft. Myers, where is that? And more importantly, how long is this contract good for?
Nevermind, I just went to the URL you listed and found out that the position is in Florida, for up to 3 months. Thanks.
Rod
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