Date Conversion

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Date Conversion

chad_hainline

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Points: 62
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September 10, 2008 at 4:44 am

#190562

I have at a table whihc for export purposes to an accounting software needs to have the invoice date in a dd/mm/yyyy format, which is not a problem. But for the purposes of reports, I really need the date in a mm/dd/yyyy format. I attempted to do a datepart and concatenate in the correct order, but get an out of range error. What am I missing?
Thank you!

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MarkusB SSC-Dedicated Points: 37370 More actions · Answer 1

The CONVERT function offers lots of different data styles. See Books Online for details.

[font="Verdana"]Markus Bohse[/font]

ChrisM@Work SSC Guru Points: 186127 More actions · Answer 2

chad_hainline (9/10/2008)
I have at a table whihc for export purposes to an accounting software needs to have the invoice date in a dd/mm/yyyy format, which is not a problem. But for the purposes of reports, I really need the date in a mm/dd/yyyy format. I attempted to do a datepart and concatenate in the correct order, but get an out of range error. What am I missing?
Thank you!

What datatype is your invoice date?

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

chad_hainline Valued Member Points: 62 More actions · Answer 3

The original format is a varchar. I attemmpted to do a Convert(varchar,date,101) earlier, but the results came back unchanged.

ChrisM@Work SSC Guru Points: 186127 More actions · Answer 4

If it's varchar then this would do the trick:

[font="Courier New"]DROP TABLE #Test

CREATE TABLE #Test (mmddyyyy VARCHAR(10))

INSERT INTO #Test

SELECT '01/01/2008' UNION ALL

SELECT '31/01/2008' UNION ALL

SELECT '01/02/2008' UNION ALL

SELECT '28/02/2008'

SELECT mmddyyyy,

SUBSTRING(mmddyyyy,4,2) + '/' + SUBSTRING(mmddyyyy,1,2) + '/' + RIGHT(mmddyyyy,4) AS ddmmyyyy

FROM #Test

[/font]

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

chad_hainline Valued Member Points: 62 More actions · Answer 5

chad_hainline

Valued Member

Points: 62

September 10, 2008 at 8:21 am

#869684

Thank you very much! Worked like a charm!